PHP preg_match 进入字符串之间
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PHP preg_match get in between string
提问by Kevin King
I'm trying to get the string hello world.
我正在尝试获取 string hello world。
This is what I've got so far:
这是我到目前为止所得到的：
$file = "1232#hello world#";
preg_match("#1232\#(.*)\##", $file, $match)
回答by Michael Berkowski
It is recommended to use a delimiter other than #since your string contains #, and a non-greedy (.*?)to capture the characters before #. Incidentally, #does not need to be escaped in the expression if it is not also the delimiter.
建议使用分隔符而不是#因为您的字符串包含#，并且使用非贪婪(.*?)来捕获 之前的字符#。顺便说一句，#如果它不是分隔符，则不需要在表达式中进行转义。
$file = "1232#hello world#";
preg_match('/1232#(.*?)#/', $file, $match);
var_dump($match);
// Prints:
array(2) {
[0]=>
string(17) "1232#hello world#"
[1]=>
string(11) "hello world"
}
Even better is to use [^#]+(or *instead of +if characters may not be present) to match all characters up to the next #.
更好的是使用[^#]+（或*代替+if 字符可能不存在）来匹配所有字符直到下一个#.
preg_match('/1232#([^#]+)#/', $file, $match);
回答by ?mega
回答by Jevon McPherson
What if you want the delimiter to also be included in the array, this would be more usefull for preg_split where you might not want each array element to begin and end with the delimiters, the example im about to show would would include the delimeters inside the array values. this would be what you would need preg_match('/\#(.*?)#/', $file, $match); print_r($match);this would output array(
[0]=> #hello world#
)
如果您希望分隔符也包含在数组中，这对于 preg_split 会更有用，因为您可能不希望每个数组元素以分隔符开头和结尾，我即将展示的示例将包含分隔符数组值。这将是你需要的，preg_match('/\#(.*?)#/', $file, $match); print_r($match);这将输出array(
[0]=> #hello world#
)
回答by Sean Redmond
It looks to me like you just have to get $match[1]:
在我看来，你只需要得到$match[1]：
php > $file = "1232#hello world#";
php > preg_match("/1232\#(.*)\#/", $file, $match);
php > print_r($match);
Array
(
[0] => 1232#hello world#
[1] => hello world
)
php > print_r($match[1]);
hello world
Are you getting different results?
你得到不同的结果吗？
回答by Pankaj Khairnar
preg_match('/1232#(.*)#$/', $file, $match);
