php 使用 call_user_func 传递参数？
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Passing parameters with call_user_func?
提问by Serguei Fedorov
Is there a way to call a function using call_user_func and pass it parameters? For instance I have
有没有办法使用 call_user_func 调用函数并传递参数？例如我有
function test($args)
{
echo "I DID IT!";
}
however I cannot call this function because it has a paramter which is not being passed by
但是我不能调用这个函数，因为它有一个没有被传递的参数
call_user_func("test");
is there a way to call the function and provide parameters to it? (for instance, the ability to pass in a list arguments)? Any help is greatly appreciated!
有没有办法调用该函数并为其提供参数？（例如，传递列表参数的能力）？任何帮助是极大的赞赏！
采纳答案by Dreen
Use call_user_func_array, you can supply a list of parameters as array.
使用call_user_func_array，您可以提供参数列表作为数组。
回答by Francis Avila
If you were to read the documentationyou would see that call_user_func()accepts a variable number of arguments:
如果您要阅读文档，您会看到它call_user_func()接受可变数量的参数：
call_user_func('test', 'argument1', 'argument2');
You can also use call_user_func_array('callback', array('array','of','arguments')).
您也可以使用call_user_func_array('callback', array('array','of','arguments')).
