Linux 将命令输出分配给 shell 变量
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Assigning command output to a shell variable
提问by Richeek
I am trying to assign output of a cut command to a variable, however I am running into a strange problem. I am using tcsh shell.
我试图将 cut 命令的输出分配给一个变量，但是我遇到了一个奇怪的问题。我正在使用 tcsh 外壳。
$echo $set a=`cut -f2 -d' ' test.txt`
Missing }. //This is the output I am getting
tcsh
This is the command I am running:
这是我正在运行的命令：
{ {corner
Now the file is real simple (well this is the not the file I was working on but I reduced the problem to this.)
现在文件非常简单（好吧，这不是我正在处理的文件，但我将问题简化为这个。）
Test.txt:
测试.txt：
{ {corner}
Thats it! This is the file. If I change the file to this:
就是这样！这是文件。如果我将文件更改为：
$echo $a
corner //Please note its not {corner} but corner
Statement works but "a" gets the following value:
语句有效，但“a”获得以下值：
set a="`cut -f2 -d' ' test.txt`"
Hence I think that shell is trying to execute {corneras a command and since its missing the closing brace shell complains. Does anyone have any idea why its showing this behavior? My understanding is that it should just assign the output of cut to the variable but looks like its assigning it recursively!
Newbie
因此，我认为 shell 试图{corner作为命令执行 ，并且由于缺少右括号 shell 会抱怨。有谁知道为什么它会表现出这种行为？我的理解是它应该只将 cut 的输出分配给变量，但看起来它是递归分配的！新手
采纳答案by ring bearer
You have to wrap it around double quotes
你必须把它用双引号括起来
echo "$a"
Same applies to uses such as echo
同样适用于诸如 echo
{corner
Output
输出
##代码##