数组到字符串的转换 Laravel 5.2
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Array to string conversion Laravel 5.2
提问by Ivan Peri?a Loga
I'm working on project, and I need help with converting array list to string.
我正在处理项目，我需要帮助将数组列表转换为字符串。
This is my controller:
这是我的控制器：
public function editprofila($id)
{
$user = User::findOrFail($id);
$gradovi = Grad::all();
$nazivGrada = DB::table('grad')
->select('grad.naziv_grada')
->join('users', 'grad.id', '=', 'users.id_grada')
->where('grad.id', '=', Auth::user()->id_grada)
->get();
if ($user->id == Auth::user()->id || Auth::user()->legenda == 1) {
return view('korisnik.uredivanje_profila',
compact('user', 'gradovi', 'nazivGrada')
);
}
}
How can select one value from options by nazivGrada such as eng. nameCity?
如何从 nazivGrada 的选项中选择一个值，例如eng。名称城市？
<select class="form-control" name="id_grada" id="id_grada">
@foreach($gradovi as $grad)
<option value="{{$grad->id}}" selected="">{{$grad->naziv_grada}}</option>
@endforeach
<option value="{{Auth::user()->id_grada}}" selected="selected">{{''.$nazivGrada.''}}</option>
</select>
My problem is that $nazivGradais Array list like this,
我的问题是$nazivGrada像这样的数组列表，
[{"naziv_grada":"Rovinj"}]
and I get an error; Array to string conversion.
我得到一个错误；数组到字符串的转换。
回答by Jordan Plamondon
What is happening if you do
如果你这样做会发生什么
$nazivGrada = DB::table('grad')
->select('grad.naziv_grada')
->join('users', 'grad.id', '=', 'users.id_grada')
->where('grad.id', '=', Auth::user()->id_grada)
->first();
And then in you view:
然后在你看来：
<option value="{{Auth::user()->id_grada}}" selected="selected">{{ $nazivGrada->naziv_grada }}</option>
回答by TheDrot
You don't need the extra query for $nazivGrada.
您不需要对 $nazivGrada 进行额外查询。
In template you can simply do:
在模板中，您可以简单地执行以下操作：
@foreach($gradovi as $grad)
<option value="{{$grad->id}}" selected="{{ $grad->id == Auth::user()->id_grada ? 'selected' : '' }}">{{$grad->naziv_grada}}</option>
@endforeach
