Java 如何配置 Swagger UI、Jersey 和文件上传?
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How to configure Swagger UI, Jersey and file upload?
提问by Pierre Henry
I have a Jersey service with a file upload method that looks like this (simplified):
我有一个带有文件上传方法的 Jersey 服务,如下所示(简化):
@POST
@Path("/{observationId : [a-zA-Z0-9_]+}/files")
@Produces({ MediaType.APPLICATION_JSON})
@Consumes(MediaType.MULTIPART_FORM_DATA)
@ApiOperation(
value = "Add a file to an observation",
notes = "Adds a file to an observation and returns a JSON representation of the uploaded file.",
response = ObservationMediaFile.class
)
@ApiResponses({
@ApiResponse(code = 404, message = "Observation not found. Invalid observation ID."),
@ApiResponse(code = 406, message= "The media type of the uploaded file is not supported. Currently supported types are 'images/*' where '*' can be 'jpeg', 'gif', 'png' or 'tiff',")
})
public RestResponse<ObservationMediaFile> addFileToObservation(
@PathParam("observationId") Long observationId,
@FormDataParam("file") InputStream is,
@FormDataParam("file") FormDataContentDisposition fileDetail,
@FormDataParam("fileBodyPart") FormDataBodyPart body
){
MediaType type = body.getMediaType();
//Validate the media type of the uploaded file...
if( /* validate it is an image */ ){
throw new NotAcceptableException("Not an image. Get out.");
}
//do something with the content of the file
try{
byte[] bytes = IOUtils.toByteArray(is);
}catch(IOException e){}
//return response...
}
It works and I can test it successfully using Postman extension in Chrome.
它有效,我可以在 Chrome 中使用 Postman 扩展成功测试它。
However, Swagger sees 2 parameters named "file". Somehow it seems to understand that the InputStream
parameter and the FormDataContentDisposition
parameter are actually 2 parts of the same file
parameter, but it fails to see that for the FormDataBodyPart
parameter.
但是,Swagger 看到了 2 个名为“file”的参数。不知何故,它似乎明白InputStream
参数和FormDataContentDisposition
参数实际上是同一个file
参数的2 个部分,但它没有看到FormDataBodyPart
参数。
This is the Swagger JSON for the parameters :
这是参数的 Swagger JSON:
parameters: [
{
name: "observationId",
required: true,
type: "integer",
format: "int64",
paramType: "path",
allowMultiple: false
},
{
name: "file",
required: false,
type: "File",
paramType: "body",
allowMultiple: false
},
{
name: "fileBodyPart",
required: false,
type: "FormDataBodyPart",
paramType: "form",
allowMultiple: false
}]
As a result, Swagger UI generates a file picker field, and an extra text field for the FormDataBodyPart argument :
因此,Swagger UI 会为 FormDataBodyPart 参数生成一个文件选择器字段和一个额外的文本字段:
So when I pick a file and submit the form in Swagger UI, I end up reading the content of the text field in the InputStream instead of the content of the uploaded file. And if I leave the textfield empty, I get the name of the file.
因此,当我选择一个文件并在 Swagger UI 中提交表单时,我最终会读取 InputStream 中文本字段的内容,而不是上传文件的内容。如果我将文本字段留空,我会得到文件的名称。
How can I instruct Swagger to ignore the FormDataBodyPart parameter ?
如何指示 Swagger 忽略 FormDataBodyPart 参数?
Alternatively, as a work-around, how can I obtain the media type of the uploaded file without the FormDataBodyPart object ?
或者,作为一种解决方法,如何在没有 FormDataBodyPart 对象的情况下获取上传文件的媒体类型?
I use Jersey 2.7 and swagger-jersey2-jaxrs_2.10 version 1.3.4.
我使用 Jersey 2.7 和 swagger-jersey2-jaxrs_2.10 版本 1.3.4。
采纳答案by user2362658
Create a swagger filter for jersey and then mark the parameter as internal or some other string you are filtering on. This is also shown in this example:
为球衣创建一个 swagger 过滤器,然后将参数标记为内部或您正在过滤的其他一些字符串。这也显示在此示例中:
Your service method will have this parameter annotation
你的服务方法会有这个参数注解
@ApiParam(access = "internal") @FormDataParam("file") FormDataBodyPart body,
Your filter will look for it like this:
你的过滤器会像这样寻找它:
public boolean isParamAllowed(Parameter parameter, Operation operation, ApiDescription api,
Map<String, List<String>> params, Map<String, String> cookies, Map<String, List<String>> headers) {
if ((parameter.paramAccess().isDefined() && parameter.paramAccess().get().equals("internal")))
return false;
else
return true;
}
Register your swagger filter for jersey and then it will not return that field and swagger-ui will not show it which will fix your upload problem.
为球衣注册您的 swagger 过滤器,然后它不会返回该字段,并且 swagger-ui 不会显示它,这将解决您的上传问题。
<init-param>
<param-name>swagger.filter</param-name>
<param-value>your.company.package.ApiAuthorizationFilterImpl</param-value>
</init-param>
回答by FinnTheHuman
It's unclear when this was added to Jersey but a note at the very end of the Multipart section says "@FormDataParam annotation can be also used on fields". Sure enough you can do this:
不清楚何时将其添加到 Jersey,但 Multipart 部分最后的注释说“ @FormDataParam 注释也可以用于字段”。果然你可以这样做:
@FormDataParam(value="file") FormDataContentDisposition fileDisposition;
@FormDataParam("fileBodyPart") FormDataBodyPart body;
@Path("/v1/source")
@POST
@Consumes(MediaType.MULTIPART_FORM_DATA)
@Produces({ MediaType.APPLICATION_JSON})
@ApiOperation(
value = "Create a new Source from an uploaded file.",
response = Source.class
)
public Response makeSource(
@FormDataParam(value="file") InputStream inputStream
)
{
logger.info(fileDisposition.toString());
return makeSourceRaw(inputStream, fileDisposition.getFileName());
}
This provides the FormDataContentDisposition but makes it "invisible" to Swagger.
这提供了 FormDataContentDisposition 但使其对 Swagger“不可见”。
Update: This works but not if there are other resources defined (@Path annotations) that don't take FormDataContentDisposition. If there are then Jersey fails at runtime because it can't fill in the fileDisposition field.
更新:这有效,但如果定义了其他不采用 FormDataContentDisposition 的资源(@Path 注释),则无效。如果有那么 Jersey 在运行时失败,因为它无法填写 fileDisposition 字段。
A better solution if you're using a recent version of Swagger to simply mark the parameter as hidden like so.
如果您使用最新版本的 Swagger 来简单地将参数标记为隐藏,这是一个更好的解决方案。
@FormDataParam("fileBodyPart") FormDataBodyPart body;
@Path("/v1/source")
@POST
@Consumes(MediaType.MULTIPART_FORM_DATA)
@Produces({ MediaType.APPLICATION_JSON})
@ApiOperation(
value = "Create a new Source from an uploaded file.",
response = Source.class
)
public Response makeSource(
@FormDataParam(value="file") InputStream inputStream,
@ApiParam(hidden=true) @FormDataParam(value="file") FormDataContentDisposition fileDisposition;
)
{
logger.info(fileDisposition.toString());
return makeSourceRaw(inputStream, fileDisposition.getFileName());
}