多个值的 Javascript 索引
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Javascript index of for multiple values
提问by coolguy
Im having a multdimensional javascript arrays like this.
我有一个像这样的多维 javascript 数组。
[
["9", "16", "19", "24", "29", "38"],
["9", "15", "19", "24", "29", "38"],
["10", "16", "19", "24", "29", "38"],
["9", "16", "17", "19", "24", "29", "39"],
["10", "16", "17", "19", "24", "29", "39"],
["9", "15", "21", "24", "29", "38"]
.......
.......
]
Around 40 to be exact
准确的说是40左右
and im having an another array called check with the following values
我有一个名为 check 的另一个数组，其中包含以下值
[9,10] //This is of size two for example,it may contain any number of elements BUT it only contains elements(digits) from the multidimensional array above
What i want is i need to make the multidimensional array unique based for the check array elements
我想要的是我需要根据检查数组元素使多维数组唯一
1.Example if check array is [15]Then multidimensional array would be
1.Example if check array is [15]then multidimensional array will be
[
["9", "15", "19", "24", "29", "38"],
//All the results which contain 15
]
2.Example if check array is [15,21]Then multidimensional array would be
2.Example if check array is [15,21]then multidimensional array will be
[
["9", "15", "21", "24", "29", "38"]
//simply containing 15 AND 21.Please note previous example has only 15 in it not 21
//I need an AND not an OR
]
I had tried the JavaScript IndexOf method BUt it is getting me an OR'ed result not AND
我曾尝试过 JavaScript IndexOf 方法，但它给我的结果不是 AND
Thanks in Advance
提前致谢
采纳答案by nnnnnn
You can use the .filter()method:
您可以使用以下.filter()方法：
var mainArray = [ /* your array here */ ],
check = ["15", "21"],
result;
result = mainArray.filter(function(val) {
for (var i = 0; i < check.length; i++)
if (val.indexOf(check[i]) === -1)
return false;
return true;
});
console.log(result);
Demo: http://jsfiddle.net/nnnnnn/Dq6YR/
演示：http: //jsfiddle.net/nnnnnn/Dq6YR/
Note that .filter()is not supported by IE until version 9, but you can fix that.
请注意，.filter()直到版本 9 才支持 IE，但您可以修复该.
回答by pimvdb
Using .filterand .every, you can filter the rows for which every argument is apparent in the row:
使用.filterand .every，您可以过滤行中每个参数都显而易见的行：
var filter = function(args) {
return arr.filter(function(row) {
return args.every(function(arg) {
return ~row.indexOf(String(arg)); // [15] should search for ["15"]
});
});
};
.everyeffectively does an ANDoperation here; for ORyou could use .someinstead. Those array functions are available on newer browsers.
.everyAND在这里有效地进行操作；因为OR你可以.some改用。这些数组函数在较新的浏览器上可用。
回答by Amberlamps
There is also a solution that is not using filter()or every():
还有一个不使用filter()or的解决方案every()：
// function
function AndArray(start, check) {
this.stripArray = function(element, array) {
var _array = [];
for(var i = 0; i < array.length; i++)
for(var j = 0; j < array[i].length; j++)
if(element == array[i][j]) _array.push(array[i]);
return _array;
}
for(var k = 0; k < start.length; k++)
if(start.length > 0) start = this.stripArray(check[k], start);
return start;
}
// use
var check = [15, 21];
var start= [[ 15, 6 , 8], [3, 21, 56], [15, 3, 21]];
console.log(AndArray(start, check));
回答by Terrel Jones Jr.
This should do it
这应该做
var checkURL = function (url) {
var final = false;
if (url.indexOf('jpg') > -1) {
final = true
}
if (url.indexOf('jpeg') > -1) {
final = true
}
if (url.indexOf('gif') > -1) {
final = true
}
if (url.indexOf('png') > -1) {
final = true
}
return final
}