java & 运算符有两个整数？
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java & operator with two integers?
提问by nife552
From what I understand the & operator is similar to the && operator except that the && only checks the second if the first is true, while the & checks both regardless of the result of the first one. Basically the && just saves a little time and power.
据我了解，& 运算符与 && 运算符类似，不同之处在于 && 仅在第一个为真时才检查第二个，而无论第一个的结果如何，& 都会检查两者。基本上 && 只是节省了一点时间和力量。
If that is so, then how does this code work?
如果是这样，那么这段代码是如何工作的？
int l = 0;
if ((l & 8) != 0 && (l & 4) == 0){ do something}
what does the (l & 8)and the (l & 4)do?
What does the & do in this case?
什么是(l & 8)和(l & 4)呢？& 在这种情况下做什么？
回答by Raffaele Rossi
& and && are two different operators but the difference is not what you've described.
& 和 && 是两个不同的运算符，但区别不是您所描述的。
& does the bit-wise AND of two integers and produces a third integer whose bit are set to 1 if both corresponding bits in the two source integers are both set to 1; 0 otherwise.
& 对两个整数进行按位与运算，如果两个源整数中的相应位都设置为 1，则生成第三个整数，该整数的位设置为 1；0 否则。
&& applies only to two booleans and returns a third boolean which will be true if both the input booleans are true; false otherwise.
&& 仅适用于两个布尔值并返回第三个布尔值，如果两个输入布尔值都为真，则该值为真；否则为假。
