bash 我们什么时候需要在 shell 变量周围使用花括号?

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时间:2020-09-09 21:26:52  来源:igfitidea点击:

When do we need curly braces around shell variables?

bashshellsyntaxcurly-braces

提问by New User

In shell scripts, when do we use {}when expanding variables?

在shell脚本中,我们{}什么时候在扩展变量时使用?

For example, I have seen the following:

例如,我看到了以下内容:

var=10        # Declare variable

echo "${var}" # One use of the variable
echo "$var"   # Another use of the variable

Is there a significant difference, or is it just style? Is one preferred over the other?

是否有显着差异,或者只是风格?一个比另一个更受欢迎吗?

回答by Fred Foo

In this particular example, it makes no difference. However, the {}in ${}are useful if you want to expand the variable fooin the string

在这个特定的例子中,它没有区别。但是,如果您想扩展字符串中的变量,则{}in${}很有用foo

"${foo}bar"

since "$foobar"would instead expand the variable identified by foobar.

因为"$foobar"会扩展由 标识的变量foobar

Curly braces are also unconditionally required when:

在以下情况下也无条件地需要花括号:

  • expanding array elements, as in ${array[42]}
  • using parameter expansion operations, as in ${filename%.*}(remove extension)
  • expanding positional parameters beyond 9: "$8 $9 ${10} ${11}"
  • 扩展数组元素,如 ${array[42]}
  • 使用参数扩展操作,如${filename%.*}(删除扩展)
  • 扩展位置参数超过 9: "$8 $9 ${10} ${11}"

Doing this everywhere, instead of just in potentially ambiguous cases, canbe considered good programming practice. This is both for consistency and to avoid surprises like $foo_$bar.jpg, where it's not visually obvious that the underscore becomes part of the variable name.

在任何地方都这样做,而不仅仅是在潜在的模棱两可的情况下,可以被认为是良好的编程实践。这既是为了保持一致性,也是为了避免意外,比如$foo_$bar.jpg下划线成为变量名称的一部分在视觉上并不明显。

回答by Aaron McDaid

Variables are declared and assigned without $and without {}. You have to use

变量在没有$和没有的情况下声明和分配{}。你必须使用

var=10

to assign. In order to read from the variable (in other words, 'expand' the variable), you must use $.

分派。为了从变量中读取(换句话说,“扩展”变量),您必须使用$.

$var      # use the variable
${var}    # same as above
${var}bar # expand var, and append "bar" too
$varbar   # same as ${varbar}, i.e expand a variable called varbar, if it exists.

This has confused me sometimes - in other languages we refer to the variable in the same way, regardless of whether it's on the left or right of an assignment. But shell-scripting is different, $var=10doesn't do what you might think it does!

这有时让我感到困惑 - 在其他语言中,我们以相同的方式引用变量,无论它是在赋值的左侧还是右侧。但是 shell 脚本是不同的,$var=10它不会像你想象的那样做!

回答by glenn Hymanman

You use {}for grouping. The braces are required to dereference array elements. Example:

{}用于分组。需要大括号来取消引用数组元素。例子:

dir=(*)           # store the contents of the directory into an array
echo "${dir[0]}"  # get the first entry.
echo "$dir[0]"    # incorrect

回答by SierraX

You are also able to do some text manipulation inside the braces:

您还可以在大括号内进行一些文本操作:

STRING="./folder/subfolder/file.txt"
echo ${STRING} ${STRING%/*/*}

Result:

结果:

./folder/subfolder/file.txt ./folder

or

或者

STRING="This is a string"
echo ${STRING// /_}

Result:

结果:

This_is_a_string

You are right in "regular variables" are not needed... But it is more helpful for the debugging and to read a script.

您是对的,不需要“常规变量”......但它对调试和阅读脚本更有帮助。

回答by Sridhar Sarnobat

The end of the variable name is usually signified by a space or newline. But what if we don't want a space or newline after printing the variable value? The curly braces tell the shell interpreter where the end of the variable name is.

变量名的结尾通常由空格或换行符表示。但是如果我们在打印变量值后不想要空格或换行符怎么办?花括号告诉 shell 解释器变量名的结尾在哪里。

Classic Example 1) - shell variable without trailing whitespace

经典示例 1) - 没有尾随空格的 shell 变量

TIME=10

# WRONG: no such variable called 'TIMEsecs'
echo "Time taken = $TIMEsecs"

# What we want is $TIME followed by "secs" with no whitespace between the two.
echo "Time taken = ${TIME}secs"

Example 2) Java classpath with versioned jars

示例 2) 带有版本化 jar 的 Java 类路径

# WRONG - no such variable LATESTVERSION_src
CLASSPATH=hibernate-$LATESTVERSION_src.zip:hibernate_$LATEST_VERSION.jar

# RIGHT
CLASSPATH=hibernate-${LATESTVERSION}_src.zip:hibernate_$LATEST_VERSION.jar

(Fred's answer already states this but his example is a bit too abstract)

(弗雷德的回答已经说明了这一点,但他的例子有点太抽象了)

回答by codeforester

Curly braces are always needed for accessing array elements and carrying out brace expansion.

访问数组元素和执行大括号扩展总是需要大括号。

It's good to be not over-cautious and use {}for shell variable expansion even when there is no scope for ambiguity.

{}即使没有歧义,也不要过度谨慎并用于 shell 变量扩展。

For example:

例如:

dir=log
prog=foo
path=/var/${dir}/${prog}      # excessive use of {}, not needed since / can't be a part of a shell variable name
logfile=${path}/${prog}.log   # same as above, . can't be a part of a shell variable name
path_copy=${path}             # {} is totally unnecessary
archive=${logfile}_arch       # {} is needed since _ can be a part of shell variable name

So, it is better to write the three lines as:

因此,最好将三行写为:

path=/var/$dir/$prog
logfile=$path/$prog.log
path_copy=$path

which is definitely more readable.

这绝对更具可读性。

Since a variable name can't start with a digit, shell doesn't need {}around numbered variables (like $1, $2etc.) unless such expansion is followed by a digit. That's too subtle and it does make to explicitly use {}in such contexts:

由于变量名称不能以数字开头,壳不需要{}围绕编号的变量(如$1$2等),除非这样的膨胀被后跟数字。这太微妙了,它确实可以{}在这种情况下明确使用:

set app      # set  to app
fruit=le   # sets fruit to apple, but confusing
fruit=le # sets fruit to apple, makes the intention clear


See:

看:

回答by Fabio Natalini

Following SierraX and Peter's suggestion about text manipulation, curly brackets {}are used to pass a variable to a command, for instance:

遵循 SierraX 和 Peter 关于文本操作的建议,大括号{}用于将变量传递给命令,例如:

Let's say you have a sposi.txtfile containing the first line of a well-known Italian novel:

假设您有一个sposi.txt文件,其中包含一部著名的意大利小说的第一行:

> sposi="somewhere/myfolder/sposi.txt"
> cat $sposi

Ouput: quel ramo del lago di como che volge a mezzogiorno

输出: quel ramo del lago di como che volge a mezzogiorno

Now create two variables:

现在创建两个变量:

# Search the 2nd word found in the file that "sposi" variable points to
> word=$(cat $sposi | cut -d " " -f 2)

# This variable will replace the word
> new_word="filone"

Now substitute the wordvariable content with the one of new_word, inside sposi.txt file

现在用sposi.txt 文件中的new_word替换单词变量 content

> sed -i "s/${word}/${new_word}/g" $sposi
> cat $sposi

Ouput: quel filone del lago di como che volge a mezzogiorno

输出: quel filone del lago di como che volge a mezzogiorno

The word "ramo" has been replaced.

“ramo”一词已被替换。