Python 类型错误：“dict”对象在使用 dict() 时不可调用
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TypeError: 'dict' object is not callable while using dict( )
提问by Masquerade0097
I was using Python 2.7.12 (default, Nov 19 2016, 06:48:10) [GCC 5.4.0 20160609] on linux2 , when i ran the folllowing code in it the corresponding error is shown .I searched a lot about this but am unable to find why is it so
我在 linux2 上使用 Python 2.7.12（默认，2016 年 11 月 19 日，06:48:10）[GCC 5.4.0 20160609]，当我在其中运行以下代码时，会显示相应的错误。我对此进行了很多搜索但我无法找到为什么会这样
>>> bob=dict(name='bob smith',age=42,pay='10000',job='dev')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'dict' object is not callable
回答by Right leg
In a fresh interpreter:
在一个新的解释器中：
>>> bob=dict(name='bob smith',age=42,pay='10000',job='dev')
>>> bob
{'age': 42, 'pay': '10000', 'job': 'dev', 'name': 'bob smith'}
However, you are getting a TypeError:
但是，您将获得TypeError：
TypeError: 'dict' object is not callable
类型错误：“dict”对象不可调用
This error you get tells you that yourdictis not callable.
你得到的这个错误告诉你你dict是不可调用的。
Since mydictis callable when I open a fresh interpreter, it means that yourdictis different.
因为当我打开一个新的解释器时mydict是可调用的，这意味着你dict的不同。
Most likely, you defined a dictvariable, which overrode the built-in dict. Look for the
最有可能的是，您定义了一个dict变量，该变量覆盖了内置的dict. 寻找
dict = {...}
line, and rename your variable.
行，并重命名您的变量。
As pointed out by @Rob?, don't use built-in names for your variables. Especially avoid the tempting str, list, and so on.
回答by Rob?
On a previous line in that interactive session, you have rebound the dictname to some variable. Perhaps you have a line like dict={1:2}or dict=dict(one=1, two=2).
在该交互式会话的前一行中，您已将dict名称重新绑定到某个变量。也许你有一行像dict={1:2}或dict=dict(one=1, two=2)。
Here is one such session:
这是一个这样的会议：
>>> dict=dict(one=1)
>>> bob=dict(name='bob smith',age=42,pay='10000',job='dev')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'dict' object is not callable
>>>
As a general rule, one should not use built-in type names as variable names, to prevent this error.
作为一般规则，不应使用内置类型名称作为变量名称，以防止出现此错误。
回答by Peter Gottesman
edit: Ignore this, I am told this is bad practice.
编辑：忽略这一点，有人告诉我这是不好的做法。
As mgilson stated, the issue is likely that you have a variable called dict. The solution to this would be to run
正如 mgilson 所说，问题很可能是您有一个名为 dict 的变量。解决这个问题的方法是运行
del dict
which deletes the variable by that name.
删除该名称的变量。
