python 如何从 range() 函数中获取最后一个数字？
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How do I get the last number from the range() function?
提问by RedBlueThing
Is there a way to get the last number from the range()function?
I need to get the last number in a Fibonacci sequence for first 20 terms or should I use a list instead of range()?
有没有办法从range()函数中获取最后一个数字？我需要获取前 20 项的斐波那契数列中的最后一个数字，还是应该使用列表而不是range()？
回答by RedBlueThing
Not quite sure what you are after here but here goes:
不太确定你在这里追求什么，但这里有：
rangeList = range(0,21)
lastNumber = rangeList[len(rangeList)-1:][0]
or:
或者：
lastNumber = rangeList[-1]
回答by vezult
by in a range, do you mean last value provided by a generator? If so, you can do something like this:
by in a range，你的意思是生成器提供的最后一个值吗？如果是这样，您可以执行以下操作：
def fibonacci(iterations):
# generate your fibonacci numbers here...
[x for x in fibonacci(20)][-1]
That would get you the last generated value.
这将为您提供最后生成的值。
回答by Stefan Kendall
I don't think anyone considered that you need fibonacci numbers. No, you'll have to store each number to build the fibonacci sequence recursively, but there is a formula to get the nth term of the fibonacci sequence.
我认为没有人认为您需要斐波那契数字。不，您必须存储每个数字以递归构建斐波那契数列，但有一个公式可以获取斐波那契数列的第 n 项。
If you need the last number of a list, use myList[-1].
如果需要列表的最后一个数字，请使用 myList[-1]。
回答by John T
Is this what you're after?
这是你追求的吗？
somerange = range(0,20)
print len(somerange) # if you want 20
print len(somerange)-1 # if you want 19
now if you want the number or item contained in a list...
现在，如果您想要列表中包含的数字或项目...
x = [1,2,3,4]
print x[len(x)-1]
# OR
print x[-1] # go back 1 element from current index 0, takes you to list end
