Python 类型错误：尝试更改数组列表的某些元素时，列表索引必须是整数，而不是元组
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TypeError: list indices must be integers, not tuple when trying to alter certain elements of a list of arrays
提问by Orange Pukeko
I have a list of 2 by n arrays of x and y coordinates.
我有一个由 x 和 y 坐标组成的 2 x n 数组的列表。
old: [array([[1, 2, 3], [4, 5, 6]]), array([[10, 20, 30], [40, 50, 60]])]
I am trying to shift the y-coordinates, the second row of each array, by a certain value 'shift'. However, when I try to do this by the method below, I get the an error:
我试图将每个数组的第二行 y 坐标移动某个值“移位”。但是，当我尝试通过以下方法执行此操作时，出现错误：
"TypeError: list indices must be integers, not tuple when trying to alter certain elements of a list of arrays."
“类型错误：在尝试更改数组列表的某些元素时，列表索引必须是整数，而不是元组。”
import pylab
def shiftY(old,shift):
new = list([])
for i in arange(len(old)):
y = old[i][1,:] + shift
newItem = array([old[:,0],y])
new.append(newItem)
return new
old = list()
old.append(arr
ay([[1, 2, 3], [4, 5, 6]]))
old.append(array([[10,20,30],[40,50,60]]))
shift =3
new=shiftY(old,shift)
print(new)
Traceback:
追溯：
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "C:\Python27_32bit\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 540, in runfile
execfile(filename, namespace)
File "C:/Users/tald574/testShifty.py", line 25, in <module>
new=shiftY(old,shift)
File "C:/Users/tald574/testShifty.py", line 15, in shiftY
newItem = array([old[:,0],y])
TypeError: list indices must be integers, not tuple
I can't see what I am doing wrong as newItemis not even supposed to be a list, it should be a 2D array. Would appreciate it if someone can tell me what I do wrong an how to fix it.
我看不出我做错了什么，因为newItem它甚至不应该是一个列表，它应该是一个二维数组。如果有人能告诉我我做错了什么以及如何解决它，我将不胜感激。
Thanks.
谢谢。
Edit: The expected outcome of this test would be,
编辑：这个测试的预期结果是，
new:[array([[1, 2, 3], [7, 8, 9]]), array([[10, 20, 30], [43, 53, 63]])]
采纳答案by 6c1
You don't need the commas in the list slicing notation. array[:,i]is parsed as array[:t], where t = ,iis a tuple. See herefor a rundown of list slicing.
您不需要列表切片符号中的逗号。array[:,i]被解析为array[:t], wheret = ,i是一个元组。有关列表切片的概要，请参见此处。
Tuples are defined by commas, not parentheses.
In your case, replace the lines
在您的情况下，替换行
y = old[i][1,:] + shift
newItem = array([old[:,0],y])
with
和
y = old[i][1:] + shift
newItem = array([old[:0],y])
回答by Orange Pukeko
Right, I feel stupid now.
没错，我现在觉得自己很傻。
I have been working on this for way too long and off course I figure out the answer within 15 minutes of posting this question.
我一直在研究这个问题太久了，当然我在发布这个问题的 15 分钟内就找到了答案。
I made two mistakes in the assignment of 'newitem'. instead of
我在分配“newitem”时犯了两个错误。代替
newItem = array([old[:,0],y])
I should have used:
我应该使用：
newItem = array([old[i][0,:],y])
That is, I need to access the appropriate item in the list, old[i] rather than old. And I need to access the appropriate item in the array old[i][0,:] rather than old[i][:,0]. Rookie mistake, I hope this helps someone else.
也就是说，我需要访问列表中的适当项目，old[i] 而不是 old。我需要访问数组 old[i][0,:] 而不是 old[i][:,0] 中的适当项目。菜鸟错误，我希望这对其他人有所帮助。
Edit, oh wow, only now see all the comments and answers on my question, thanks guys, I took so long because I incorporated this into my actual project, rather than just the test script. Cheers anyway.
编辑，哇哦，现在才看到我的问题的所有评论和答案，谢谢大家，我花了这么长时间，因为我将它合并到了我的实际项目中，而不仅仅是测试脚本。总之干杯。
回答by Neelu
It seems that ,is placed instead of :.
似乎,是放置而不是:.
Replace the comma with colon.
用冒号替换逗号。
Below is the correct syntax of the sublist creation from the list.
下面是从列表中创建子列表的正确语法。
list_name[start_index:end_index]
