pandas 两个 Series 对象的布尔比较
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Boolean comparison of two Series objects
提问by veor
I have two Series which have a format equal to this:
我有两个系列，它们的格式与此相同：
0 False
1 False
2 False
3 True
4 True
Name: foo, dtype: bool
0 True
1 False
2 False
3 True
4 True
Name: bar, dtype: bool
I want to create a new Series with the resulting boolean comparison from these. Something like this:
我想用这些结果的布尔比较创建一个新系列。像这样的东西：
result = foo and bar
>>> print result
0 False
1 False
2 False
3 True
4 True
Name: result, dtype: bool
Using the obvious result = foo and barsimply results in the following error:
使用明显的result = foo and bar只会导致以下错误：
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
I looked at those functions, but neither seem to do what I wish.
我查看了这些功能，但似乎都没有按照我的意愿行事。
How can I do an element-to-element boolean comparison of a Series resulting in a new Series?
如何对系列进行元素到元素的布尔比较，从而产生新系列？
回答by chrisb
You need to use the bitwise and operator &.
您需要使用按位和运算符&。
result = foo & bar
