java Java中的“西蒙说”
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"Simon says" in java
提问by Gui
"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence.
“西蒙说”是一种记忆游戏，其中“西蒙”输出 10 个字符（R、G、B、Y）的序列，用户必须重复该序列。
Create a for loop that compares the two strings starting from index 0.
创建一个 for 循环，比较从索引 0 开始的两个字符串。
For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement.
对于每场比赛，在 userScore 上加一分。在不匹配时，使用 break 语句退出循环。
Ex: The following patterns yield a userScore of 4: simonPattern: R, R, G, B, R, Y, Y, B, G, Y userPattern: R, R, G, B, B, R, Y, B, G, Y
例如：以下模式产生的 userScore 为 4： simonPattern: R, R, G, B, R, Y, Y, B, G, Y userPattern: R, R, G, B, B, R, Y, B, G, Y
import java.util.Scanner;
public class SimonSays {
public static void main (String [] args) {
String simonPattern = "";
String userPattern = "";
int userScore = 0;
int i = 0;
userScore = 0;
simonPattern = "RRGBRYYBGY";
userPattern = "RRGBBRYBGY";
/* Your solution goes here */
char s;
char u;
for (i=0;i<=10;i++) {
s = simonPattern.charAt(i);
u = userPattern.charAt(i);
if (s == u) {
userScore = userScore + 1;
continue;
}
}
System.out.println("userScore: " + userScore);
return;
}
}
And the system said:
然后系统说：
Runtime error (commonly due to an invalid array/vector access, divide by 0, etc.).
Why my code didn't work?
为什么我的代码不起作用？
回答by gomezportillo
Instead of hard-programming the length of your String (just because before you should have finger counted it and you may be wrong) you could use
你可以使用而不是硬编程你的字符串的长度（只是因为在你应该用手指计算它之前你可能是错的）
for (int i=0; i < simonPattern.length(); i++)
for (int i=0; i < simonPattern.length(); i++)
Happy coding
快乐编码
Edit: but it could alse generate an Exception, as userPattern could be smaller than simonPattern. You could check it by
编辑：但它也可能生成异常，因为 userPattern 可能小于 simonPattern。你可以通过
if (simonPattern.length() == userPattern.length()) {
userScore = userScore + 1;
continue; // this is not really needed but it may if having more else-if
} else{
break; // This will break the loop as soon as it finds a mismatch
}
}
回答by Gabriele Mariotti
The error is here:
错误在这里：
for (i=0;i<=10;i++) {
Change in
在某一方面的变化
for (i=0;i<10;i++) {
Your string has length = 10.
您的字符串长度为 10。
回答by Marko ?ivanovi?
for (i=0;i<=10;i++) {will execute 11 times (0 to 10) and you only have 10 elements in your strings. Changing the line to for (i=0;i<10;i++) {will execute proper number of times and shouldn't throw any exceptions.
for (i=0;i<=10;i++) {将执行 11 次（0 到 10）并且您的字符串中只有 10 个元素。将行更改为for (i=0;i<10;i++) {将执行适当的次数并且不应引发任何异常。
