Javascript jquery函数返回值
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Jquery function return value
提问by Stephen S.
I've created a function to iterate through a UL/LI. This works perfectly, my problem is returning the value to another variable. Is this even possible? What's the best method for this? Thanks!
我创建了一个函数来遍历 UL/LI。这很有效，我的问题是将值返回给另一个变量。这甚至可能吗？最好的方法是什么？谢谢！
function getMachine(color, qty) {
$("#getMachine li").each(function() {
var thisArray = $(this).text().split("~");
if(thisArray[0] == color&& qty>= parseInt(thisArray[1]) && qty<= parseInt(thisArray[2])) {
return thisArray[3];
}
});
}
var retval = getMachine(color, qty);
回答by Alex Turpin
I'm not entirely sure of the general purpose of the function, but you could always do this:
我不完全确定该函数的一般用途，但您始终可以这样做：
function getMachine(color, qty) {
var retval;
$("#getMachine li").each(function() {
var thisArray = $(this).text().split("~");
if(thisArray[0] == color&& qty>= parseInt(thisArray[1]) && qty<= parseInt(thisArray[2])) {
retval = thisArray[3];
return false;
}
});
return retval;
}
var retval = getMachine(color, qty);
回答by Milimetric
The return statement you have is stuck in the inner function, so it won't return from the outer function. You just need a little more code:
您拥有的 return 语句卡在内部函数中，因此它不会从外部函数返回。你只需要多一点代码：
function getMachine(color, qty) {
var returnValue = null;
$("#getMachine li").each(function() {
var thisArray = $(this).text().split("~");
if(thisArray[0] == color&& qty>= parseInt(thisArray[1]) && qty<= parseInt(thisArray[2])) {
returnValue = thisArray[3];
return false; // this breaks out of the each
}
});
return returnValue;
}
var retval = getMachine(color, qty);
