JavaScript 正则表达式只匹配 X 位数字
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JavaScript regular expression to match X digits only
提问by magenta placenta
Can someone help my pea brain figure out why my simple regular expression is not working as I am expecting/wanting it to.
有人可以帮助我的豌豆大脑弄清楚为什么我的简单正则表达式不能像我期望/想要的那样工作。
I want to match a date format of MM/DD/YYYY with exactly2 and 4 digits, so something like 01/16/1955. My code below does that, but it also matches 2+and 4+digits, so something like 011/16/1955 or 01/16/19555 (1 extra digit) pass my validation as well.
我想匹配MM / DD / YYYY与日期格式正好2和4位数，所以像1955年1月16日。我下面的代码可以做到这一点，但它也匹配2+和4+位数字，因此诸如 011/16/1955 或 01/16/19555（1 个额外数字）之类的内容也通过了我的验证。
//validate date of birth
var dob_label = $date_of_birth.find('label').text().slice(0, -1),
dob_mm = $dob_mm.val(),
dob_dd = $dob_dd.val(),
dob_yyyy = $dob_yyyy.val(),
regex_two_digit = /^\d{2}$/,
regex_four_digit = /^\d{4}$/;
if ( (regex_two_digit.test(dob_mm)) && (regex_two_digit.test(dob_dd)) && (regex_four_digit.test(dob_yyyy)) ) {
//a button is enabled here
} else {
//a validation error is thrown here and the button is disabled
}
回答by Crayon Violent
need to specify start and end of string
需要指定字符串的开始和结束
/^\d{4}$/
回答by Darrell Robert Parker
try this ^\d{1,2}\/\d{1,2}\/\d{4}$
尝试这个 ^\d{1,2}\/\d{1,2}\/\d{4}$
