Java 使用 Spring 时如何注入多个 JPA EntityManager(持久化单元)
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/28817120/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to inject multiple JPA EntityManager (persistence units) when using Spring
提问by Xorty
I need to use one database for queries (non-modifying) and one for commands (modifying). I am using Spring Data JPA, so I have two configuration classes:
我需要将一个数据库用于查询(非修改)和一个用于命令(修改)。我使用的是 Spring Data JPA,所以我有两个配置类:
@Configuration
@EnableJpaRepositories(value = "com.company.read",
entityManagerFactoryRef = "readingEntityManagerFactory",
transactionManagerRef = "readingTransactionManager")
@EnableTransactionManagement
public class SpringDataJpaReadingConfiguration {
@Bean(name = "readingEntityManagerFactory")
public EntityManagerFactory readingEntityManagerFactory() {
return Persistence.createEntityManagerFactory("persistence.reading");
}
@Bean(name = "readingExceptionTranslator")
public HibernateExceptionTranslator readingHibernateExceptionTranslator() {
return new HibernateExceptionTranslator();
}
@Bean(name = "readingTransactionManager")
public JpaTransactionManager readingTransactionManager() {
return new JpaTransactionManager();
}
}
@Configuration
@EnableJpaRepositories(value = "com.company.write",
entityManagerFactoryRef = "writingEntityManagerFactory",
transactionManagerRef = "writingTransactionManager")
@EnableTransactionManagement
public class SpringDataJpaWritingConfiguration {
@Bean(name = "writingEntityManagerFactory")
public EntityManagerFactory writingEntityManagerFactory() {
return Persistence.createEntityManagerFactory("persistence.writing");
}
@Bean(name = "writingExceptionTranslator")
public HibernateExceptionTranslator writingHibernateExceptionTranslator() {
return new HibernateExceptionTranslator();
}
@Bean(name = "writingTransactionManager")
public JpaTransactionManager writingTransactionManager() {
return new JpaTransactionManager();
}
}
In my repository I sometimes need to decide with EntityManager to use like so:
在我的存储库中,我有时需要决定使用 EntityManager 像这样使用:
@Repository
public class UserReadingRepository {
@PersistenceContext(unitName = "persistence.reading")
private EntityManager em;
// some useful queries here
}
I am using persistence unit's name as defined in my persistence.xml:
我正在使用在我的persistence.xml 中定义的持久性单元的名称:
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="persistence.reading" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<non-jta-data-source>ReadingDS</non-jta-data-source>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.show_sql" value="true" />
</properties>
</persistence-unit>
<persistence-unit name="persistence.writing" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<non-jta-data-source>WritingDS</non-jta-data-source>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
<property name="hibernate.show_sql" value="true" />
</properties>
</persistence-unit>
</persistence>
Spring throws org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'persistence.reading'
is defined. Oddly, it looks like Spring tries to instantiate a beanwith persistence unit name? Did I misconfigure something?
Spring throwsorg.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'persistence.reading'
已定义。奇怪的是,看起来 Spring 试图用持久性单元名称实例化一个 bean?我是否配置错误?
UPDATE: When I remove unitName = "persistence.reading"
from @PersistenceContext annotation, I will get following error instead:
org.springframework.beans.factory.NoUniqueBeanDefinitionException: No qualifying bean of type [javax.persistence.EntityManagerFactory] is defined: expected single matching bean but found 2: readingEntityManagerFactory,writingEntityManagerFactory
更新:当我unitName = "persistence.reading"
从 @PersistenceContext 注释中删除时,我会收到以下错误:
org.springframework.beans.factory.NoUniqueBeanDefinitionException: No qualifying bean of type [javax.persistence.EntityManagerFactory] is defined: expected single matching bean but found 2: readingEntityManagerFactory,writingEntityManagerFactory
UPDATE 2: Rohit suggested (in the comment) to wire EntityManagerFactory
instead. So I tried to do the following:
更新 2:Rohit 建议(在评论中)EntityManagerFactory
改为连接。所以我尝试执行以下操作:
@PersistenceUnit(unitName = "persistence.reading")
private EntityManagerFactory emf;
but Spring only reports: org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'persistence.reading' is defined
但 Spring 只报告: org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'persistence.reading' is defined
FINAL FIX:
Thanks to Vlad's answer, I was able to update the code to use the following (just make sure you define your dataSource
bean as well):
最终修复:感谢 Vlad 的回答,我能够更新代码以使用以下内容(只需确保您也定义了dataSource
bean):
@Bean(name = "readingEntityManagerFactory")
public EntityManagerFactory readingEntityManagerFactory() {
LocalContainerEntityManagerFactoryBean em = new LocalContainerEntityManagerFactoryBean();
em.setPersistenceUnitName("persistence.reading");
em.setDataSource(dataSource());
em.setPackagesToScan("com.company");
em.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
em.afterPropertiesSet();
return em.getObject();
}
采纳答案by Vlad Mihalcea
The EntityManageFactory
is not properly configured. You should use a LocalContainerEntityManagerFactoryBean
instead:
在EntityManageFactory
没有正确配置。您应该使用 aLocalContainerEntityManagerFactoryBean
代替:
@Bean(name = "readingEntityManagerFactory")
public EntityManagerFactory readingEntityManagerFactory() {
LocalContainerEntityManagerFactoryBean em = new LocalContainerEntityManagerFactoryBean();
em.setPersistenceUnitName("persistence.reading");
em.setDataSource(dataSource());
em.setPackagesToScan("com.company");
em.setJpaVendorAdapter(new HibernateJpaVendorAdapter());
em.afterPropertiesSet();
return em.getObject();
}
Also the JpaTransactionManager
is miss-configured too. It should be something like:
也JpaTransactionManager
配置错误。它应该是这样的:
@Bean(name = "readingTransactionManager")
public PlatformTransactionManager readingTransactionManager(){
JpaTransactionManager transactionManager = new JpaTransactionManager();
transactionManager.setEntityManagerFactory(readingEntityManagerFactory());
return transactionManager;
}
You need to do the same for both the reading and the writing EntityManager configurations.
您需要对读取和写入 EntityManager 配置执行相同的操作。