bash 通过 SSH 执行 PHP 脚本
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Executing PHP script via SSH
提问by Ry-
I want to send data to my server via SSH. The data is image files that need to be saved into directories on the server.
我想通过 SSH 将数据发送到我的服务器。数据是需要保存到服务器目录中的图像文件。
If I run the script via SSH how can I get a PHP script to read the image files?
如果我通过 SSH 运行脚本，我怎样才能获得一个 PHP 脚本来读取图像文件？
For example, if I used bash I could do
例如，如果我使用 bash 我可以做
./uploadimage.bash -image.jpg
and that would be that. But my knowledge of PHP is limited. Usually PHP uses the $_FILE array when dealing with files, as far as I know. Do I need to use this if I send the files by SSH?
就是这样。但是我对 PHP 的了解是有限的。据我所知，PHP 通常在处理文件时使用 $_FILE 数组。如果我通过 SSH 发送文件，我需要使用它吗？
回答by che
回答by Ry-
It depends on what you need to do with the images.
这取决于您需要对图像做什么。
Do you just need to echo them out to the user?
echo file_get_contents('image.jpg');Are you meaning to retrieve the command-line variables passed to the script? Use
$argv.myScript.php image.jpg # image.jpg becomes $argv[1]Do you need to do processing on the images? Use the GD functions.
$image = imagecreatefromjpeg('image.jpg'); // Do processing imagejpeg($image); // Pass a filename if you want to save it instead of output it.
回答by skyronic
If you want to simply upload a bunch of files to a remote server, your best bet is to use scpcommand, rather than PHP
如果您只想将一堆文件上传到远程服务器，最好的办法是使用scp命令，而不是 PHP
scp /your/file.png username@host:/remote/path.png
If you execute a PHP script through an SSH Session, there's no way you can send a file through SSH. You have to first copy it to the remote server and then execute the PHP which uses file_get_contentsor something like that.
如果您通过 SSH 会话执行 PHP 脚本，则无法通过 SSH 发送文件。您必须首先将其复制到远程服务器，然后执行使用的 PHPfile_get_contents或类似的东西。
If you are surethat PHP must be the recipient of the file (maybe you want to do some logic to determine the file name, path), you have to host it as a webserver, and you can use curlto upload the file, like this:
如果你确定PHP一定是文件的接收者（可能你想做一些逻辑来确定文件名、路径），你必须把它作为一个网络服务器来托管，你可以curl用来上传文件，像这样：
curl -k -F [email protected] foo.php.
