Python 绘制空心星号方块
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Drawing a hollow asterisk square
提问by Ergo
I'm trying to figure out how to turn my wholesquare into a hollow one. The few things I've tried so far haven't been very successful as I end up getting presented with a rather distorted triangle!
我想弄清楚如何把我的整个正方形变成一个空心的正方形。到目前为止，我尝试的几件事都不是很成功，因为我最终看到的是一个相当扭曲的三角形！
This is the code I have to form my square currently ..
这是我目前必须形成我的正方形的代码..
size = 5
for i in range(size):
print ('*' * size)
When run, this is the result ..
运行时，这是结果..
*****
*****
*****
*****
*****
Do I need to run ifor whilestatements when sizeis greater than 3 to specify a condition?
当大于 3时是否需要运行if或while语句size来指定条件？
采纳答案by Reed Copsey
You can print out a single '*', followed by size-2spaces, then a single '*'. This will give you the "hollow" portion. The first and last lines need the full length:
您可以打印出单个'*'，然后是size-2空格，然后是单个'*'。这将为您提供“空心”部分。第一行和最后一行需要全长：
size = 5
inner_size = size - 2
print ('*' * size)
for i in range(inner_size):
print ('*' + ' ' * inner_size + '*')
print ('*' * size)
回答by aldeb
I think this is what you want to do:
我认为这就是你想要做的：
m, n = 10, 10
for i in range(m):
for j in range(n):
print('*' if i in [0, n-1] or j in [0, m-1] else ' ', end='')
print()
Output:
输出：
**********
* *
* *
* *
* *
* *
* *
* *
* *
**********
You can also draw a triangle this way:
你也可以这样画一个三角形：
m, n = 10, 10
for i in range(m):
for j in range(n):
print('*' if i in [j, m-1] or j == 0 else ' ', end='')
print()
Output:
输出：
*
**
* *
* *
* *
* *
* *
* *
* *
**********
回答by Mikk
Heres my example:
这是我的例子：
print("Enter width")
width = int(input())
print("Enter height")
height = int(input())
for i in range(height):
if i in[0]:
print("* "*(width))
elif i in[(height-1)]:
print("* "*(width))
else:
print("*"+" "*(width-2)+" *")
input()
Output: Image link
输出：图像链接
Hope this helps everyone else, who wants to leave spaces between asteriks, while printing a rectangle and if there are any mistakes in my code let me know, because I'm a beginner myself.
希望这对其他人有所帮助，他们希望在打印矩形时在星号之间留出空格，如果我的代码中有任何错误，请告诉我，因为我自己也是初学者。
回答by Daku
size = int(input('Enter the size of square you want to print = '))
for i in range(size): # This defines the rows
for j in range(size): # This defines the columns
print('*' , end=' ') # Printing * and " end=' ' " is giving space after every * preventing from changing line
print() # Giving a command to change row after every column in a row is done
print() # Leaving one line
for k in range(size): # This defines the rows
print('* ' *size) # Defines how many times * should be multiplied
回答by ahmedov
Here is my python code for drawing a square by entered size N.
这是我的python代码，用于按输入的大小N绘制正方形。
n = int(input())
print('*' * n)
for i in range(n-2):
print ('*' + ' ' * (n-2) + '*')
print('*' * n)
Basically the first and the last print('*' * n)are drawing the top and the bottom lines and the for cycle prints the body.
基本上第一个和最后一个print('*' * n)绘制顶部和底部线条，for 循环打印主体。
Output example: N=3
输出示例：N=3
***
* *
***
Output example: N=5
输出示例：N=5
*****
* *
* *
* *
*****
回答by user9093127
Try this:
尝试这个：
size = 5
for i in range(1,size+1):
if (i==1 or i==size):
print("*"*size)
else:
print("*"+" "*(size-2),end="")
print("*")
output:
输出：
*****
* *
* *
* *
*****
回答by Vicky Kumar
Here is my python 3.6 code for drawing a square using column size and row size inputs:
这是我使用列大小和行大小输入绘制正方形的 python 3.6 代码：
column = int(input("Enter column size : "))
row = int(input("Enter row size : "))
print('* ' * column)
print(('* ' + " " * (column-2)+ '*'+'\n')*(row -2) + ('* ' * column))
回答by Vicky Kumar
You can also draw a triangle using this simple way:
您还可以使用这种简单的方法绘制三角形：
n = int(input("enter num")) for i in range (n+1):
n = int(input("enter num")) for i in range (n+1):
if 2>=i :
print (i * "*")
elif n == i:
print ("*" * i)
else:
print ("*"+" "*(i-2)+"*")
