Python 将迭代器转换为列表的最快方法
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时间：2020-08-18 12:46:27 来源:igfitidea点击:
Fastest way to convert an iterator to a list
提问by systempuntoout
Having an iteratorobject, is there something faster, better or more correct than a list comprehension to get a list of the objects returned by the iterator?
拥有一个iterator对象，是否有比列表理解更快、更好或更正确的方法来获取迭代器返回的对象列表？
user_list = [user for user in user_iterator]
采纳答案by mikerobi
list(your_iterator)
回答by kederrac
since python 3.5you can use *iterable unpacking operator:
从python 3.5 开始，您可以使用*可迭代的解包运算符：
user_list = [*your_iterator]
but the pythonic wayto do it is:
但是pythonic的方法是：
user_list = list(your_iterator)
