Python 类型错误：object() 不带参数
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TypeError: object() takes no parameters
提问by Riccardo moroletti
My code generates the following error: TypeError: object() takes no parameters
我的代码生成以下错误： TypeError: object() takes no parameters
class Graph(object):
def vertices(self):
return list(self.__graph_dict.keys())
if __name__ == "__main__":
g = { "a" : ["d"],
"b" : ["c"],
"c" : ["b", "c", "d", "e"],
"d" : ["a", "c"],
"e" : ["c"],
"f" : []
}
graph = Graph(g)
print("Vertices of graph:")
print(graph.vertices())
Is there a way I can solve this?
有没有办法解决这个问题？
采纳答案by Arthur.V
Your Graph class takes no arguments on __init__therefore when you call:
__init__因此，当您调用时，您的 Graph 类不接受任何参数：
graph = Graph(g)
图 = 图（g）
You get an error because Graph doesn't know what to do with 'g'. I think what you may want is:
您会收到错误消息，因为 Graph 不知道如何处理 'g'。我想你可能想要的是：
class Graph(object):
def __init__(self, values):
self.__graph_dict = values
def vertices(self):
return list(self.__graph_dict.keys())
