Javascript （多个）用数组替换字符串
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时间：2020-08-23 14:24:04 来源:igfitidea点击:
(Multiple) Replace string with array
提问by Simasher
I have a large string which need be replaced a few times. Such as
我有一根大绳子，需要更换几次。如
var str="Username:[UN] Location:[LC] Age:[AG] ... "
str=str.replace("[UN]","Ali")
str=str.replace("[LC]","Turkey")
str=str.replace("[AG]","29")
...
//lots of replace
...
Is there a way to put those FIND and REPLACE parameters to an array, and replace all of them at once? Such as:
有没有办法将这些 FIND 和 REPLACE 参数放入一个数组中，并一次替换所有这些参数？如：
reps = [["UN","Ali"], ["LC","Turkey"], ["AG","29"], ...]
$(str).replace(reps)
回答by kennytm
No jQuery is required.
不需要 jQuery。
var reps = {
UN: "Ali",
LC: "Turkey",
AG: "29",
...
};
return str.replace(/\[(\w+)\]/g, function(s, key) {
return reps[key] || s;
});
- The regex
/\[(\w+)\]/gfinds all substrings of the form[XYZ]. - Whenever such a pattern is found, the function in the 2nd parameter of
.replacewill be called to get the replacement. - It will search the associative array and try to return that replacement if the key exists (
reps[key]). - Otherwise, the original substring (
s) will be returned, i.e. nothing is replaced. (See In Javascript, what does it mean when there is a logical operator in a variable declaration?for how||makes this work.)
- 正则表达式
/\[(\w+)\]/g查找形式为 的所有子字符串[XYZ]。 - 每当发现这样的模式时，将调用 的第二个参数中的函数
.replace来获取替换。 - 它将搜索关联数组并尝试在键存在 (
reps[key]) 时返回该替换。 - 否则，
s将返回原始子字符串 ( )，即不替换任何内容。（请参阅在 Javascript 中，当变量声明中存在逻辑运算符时，这意味着什么？有关如何||使其工作。）
回答by Sarfraz
You can do:
你可以做：
var array = {"UN":"ALI", "LC":"Turkey", "AG":"29"};
for (var val in array) {
str = str.split(val).join(array[val]);
}
