typescript 打字稿过滤对象数组
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Typescript filter an array of objects
提问by Krishna
I want to filter my resultsarray based on the values stored in filters.
I have tried the below code. But it is not applying.
我想results根据存储在过滤器中的值过滤我的数组。我试过下面的代码。但它不适用。
let filters = {
name: ["Krishna", "Naveen"],
city : ["London"]
};
results = [
{
"name": "Krishna#Surname",
"city": "London",
"age": 23
},
{
"name": "Naveen#Surname",
"city": "London",
"age": 23
},
{
"name": "Krishna#Surname",
"city": "NewYork",
"age": 23
},
{
"name": "Praveen#Surname",
"city": "Washington",
"age": 23
}
]
this.results1 = this.multiFilter(results,filters);
multiFilter(array:any=[], filters:Object) {
const filterKeys = Object.keys(filters);
return array.filter((item) => {
return filterKeys.every(key => {
let filters1= filters[key];
return filters1.every(key1 => {
return !!~ item[key].indexOf(key1)
});
});
});
}
回答by Ele
An alternative is using the function filteralong with functions includesand some.
另一种方法是将该函数filter与函数includes和一起使用some。
let filters = { name: ["Krishna", "Naveen"], city : ["London"]},
results = [{ "name": "Krishna#Surname", "city": "London", "age": 23},{ "name": "Naveen", "city": "London", "age": 23},{ "name": "Krishna", "city": "NewYork", "age": 23},{ "name": "Praveen", "city": "Washington", "age": 23}],
result = results.filter(({name, city}) => filters.name.some(n => name.includes(n)) && filters.city.includes(city));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }回答by Nina Scholz
You could check for every filter and returns that object which matches all conditions.
您可以检查每个过滤器并返回匹配所有条件的对象。
This approach works for an arbitrary count of conditions.
这种方法适用于任意数量的条件。
function multiFilter(array, filters) {
return array.filter(o =>
Object.keys(filters).every(k =>
[].concat(filters[k]).some(v => o[k].includes(v))));
}
var filters = { name: ["Krishna", "Naveen"], city: ["London"] },
results = [{ name: "Krishna#Surname", city: "London", age: 23 }, { name: "Naveen#Surname", city: "London", age: 23 }, { name: "Krishna#Surname", city: "NewYork", age: 23 }, { name: "Praveen#Surname", city: "Washington", age: 23 }],
filtered = multiFilter(results, filters);
console.log(filtered);.as-console-wrapper { max-height: 100% !important; top: 0; }回答by Eddie
You can filterthe array and use includesto check if name and city is on the array
您可以filter使用数组并用于includes检查名称和城市是否在数组中
let filters = {name: ["Krishna", "Naveen"],city: ["London"]};
let results = [{"name": "Krishna","city": "London","age": 23},{"name": "Naveen","city": "London","age": 23},{"name": "Krishna","city": "NewYork","age": 23},{"name": "Praveen","city": "Washington","age": 23}]
let result = results.filter(o => filters.name.includes(o.name) && filters.city.includes(o.city));
console.log(result);