php 尝试验证名称字段以确保它全是字母字符或连字符或撇号
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Trying to validate a name field to be sure it is all alpha characters or a hyphen or apostrophe
提问by Bill
if(!preg_match("/[a-zA-Z'-]/",$First)) { die ("invalid first name");}
the above only flags input as invalid when the field is all numeric. combinations of letters and numbers pass ok. Some help here for a newby please. thanks.
当字段全部为数字时，上述仅将输入标记为无效。字母和数字的组合通过。请在这里为新手提供一些帮助。谢谢。
回答by Andy E
Try:
尝试：
if(!preg_match("/^[a-zA-Z'-]+$/",$First)) { die ("invalid first name");}
The ^matches the beginning of the string, the $matches the end of the string and +after a character group means "one or more" matching characters.
所述^匹配的字符串的开头，所述$字符串的末尾匹配和+之后的字符组的意思是“一个或多个”匹配的字符。
回答by cletus
You're only matching a single character. You need to add a wildcard like +(1 or more). Also you're matching anywhere in the string. You need to add anchors (^for start of string, $for end of string) to make sure there are no invalid characters.
你只匹配一个字符。您需要添加一个通配符，如+（1 个或多个）。你也匹配字符串中的任何地方。您需要添加锚点（^用于字符串的开头，$用于字符串的结尾）以确保没有无效字符。
if (!preg_match("/^[a-zA-Z'-]+$/", $First)) { die ("invalid first name");}
Alternatively you can look for a non-matching character:
或者，您可以查找不匹配的字符：
if (preg_match("/[^a-zA-Z'-]/", $First)) { die ("invalid first name");}
The ^inside the square brackets here means "any character that is NOT one of these".
在^方括号内这里的意思是“任何一个不是其中之一。”
回答by John Knoeller
In this case better to look for invalid characters than to try and match all of the characters, once a single invalid character appears, the search can quit and return failure. This is more efficient than always scanning the whole string.
在这种情况下，最好查找无效字符而不是尝试匹配所有字符，一旦出现单个无效字符，搜索就会退出并返回失败。这比总是扫描整个字符串更有效。
if (preg_match("/[^A-Za-z'-]/", $First)) { die ("invalid first name"); }
the ^ inside the set [] makes it match everything not in the set. and since the string is invalid if we have even one invalid character, there is no need for the set to have a repetition operator.
集合 [] 中的 ^ 使其匹配集合中没有的所有内容。并且由于即使我们有一个无效字符，字符串也是无效的，因此集合不需要重复运算符。
Even better would be a more helpful error message
更好的是更有用的错误消息
if (preg_match("/[^A-Za-z'-]/", $First, $Inv)) { die ("{$Inv[0]} not allowed in first name"); }
回答by Jeremy Knight
Adding accented characters is probably smart too, so that "Pierre Bézier" can fill out your form. Adding:
添加重音字符可能也很聪明，这样“Pierre Bézier”就可以填写您的表格。添加：
à-?
.. to your regex will do that. Something like this, with everything included:
.. 到你的正则表达式会做到这一点。像这样的东西，包括所有内容：
/^([a-zA-Zà-?-' ]+)$/
回答by STEEL
You can try this one, incase you want FULL NAME e.g. "JOHN RAMBO"
你可以试试这个，以防你想要全名，例如“JOHN RAMBO”
While the HTML FORM.PHP
而 HTML FORM.PHP
<div class="error"><?php echo $error['name']; ?></div>
<input name="name" type="text" value="<?php echo $input['name']; ?>" class="inputf">
PHP CONTACT PAGE
PHP 联系页面
if(!preg_match("/^[a-zA-Z'-]/", $input['name']))
{
// name is in-valid
$error['name'] = 'Invalid Name';
include('views/form.php');
}
回答by Gozie
Here's an solution I was able to come up with. Should be able to handle your validation issues for names that have apostrophes, hypens and spaces.
这是我能够想出的解决方案。应该能够处理包含撇号、连字符和空格的名称的验证问题。
if(!preg_match('/^([a-zA-Z]+[\'-]?[a-zA-Z]+[ ]?)+$/', $string))回答by cjohansson
If you use if (!preg_match("/^[a-zA-Z'-]+$/", $firstName)) {it will also match if an error occured, like a invalid regexp, because the !matches for both the return values FALSEand 0.
如果您使用if (!preg_match("/^[a-zA-Z'-]+$/", $firstName)) {它也会在发生错误时匹配，例如无效的正则表达式，因为!返回值FALSE和0.
From the PHP Manual:
preg_match() returns 1 if the pattern matches given subject, 0 if it does not, or FALSE if an error occurred.
从PHP 手册：
preg_match() returns 1 if the pattern matches given subject, 0 if it does not, or FALSE if an error occurred.
So the best way of making sure that the name is valid by your requirements is:
因此，确保名称符合您的要求的最佳方法是：
if (preg_match("/^[a-zA-Z'-]+$/", $firstName) === 1) {
die('Valid name');
} else {
die('Invalid name or error');
}
