java 在非常简单的示例中使用 EasyMock.expect() 时编译错误？
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Compile error while using EasyMock.expect() in very simple example?
提问by Bjarke Freund-Hansen
I am trying a very simple example using EasyMock, however I simply cannot make it build. I have the following test case:
我正在尝试使用EasyMock 的一个非常简单的示例，但是我根本无法构建它。我有以下测试用例：
@Test
public void testSomething()
{
SomeInterface mock = EasyMock.createMock(SomeInterface.class);
SomeBase expected = new DerivesFromSomeBase();
EasyMock.expect(mock.send(expected));
}
However I get the following error in the EasyMock.expect(...line:
但是，我EasyMock.expect(...在行中收到以下错误：
The method expect(T) in the type EasyMock is not applicable for the arguments (void)
Can somebody point me in the correct direction? I am completely lost.
有人可以指出我正确的方向吗？我完全迷失了。
回答by Jasper
If you want to test voidmethods, call the method you want to test on your mock. Then call the expectLastCall()method.
如果要测试void方法，请在模拟上调用要测试的方法。然后调用expectLastCall()方法。
Here's an example:
下面是一个例子：
@Test
public void testSomething()
{
SomeInterface mock = EasyMock.createMock(SomeInterface.class);
SomeBase expected = new DerivesFromSomeBase();
mock.send(expected);
EasyMock.expectLastCall().andAnswer(new IAnswer<Object>() {
public Object answer() {
// do additional assertions here
SomeBase arg1 = (SomeBase) EasyMock.getCurrentArguments()[0];
// return null because of void
return null;
}
});
}
回答by Biju Kunjummen
Since your send() method returns void, just call the mock method with expected values and replay:
由于您的 send() 方法返回 void，只需使用预期值调用模拟方法并重播：
SomeInterface mock = EasyMock.createMock(SomeInterface.class);
SomeBase expected = new DerivesFromSomeBase();
mock.send(expected);
replay(mock);
回答by Joshua Marble
Since you are mocking an interface, the only purpose in mocking a method would be to return a result from that method. In this case, it appears your 'send' method's return type is void. The 'EasyMock.expect' method is generic and expects a return type, which is causing the compiler to tell you that you can't use a void method because it doesn't have a return type.
由于您正在模拟接口，因此模拟方法的唯一目的是从该方法返回结果。在这种情况下，您的“发送”方法的返回类型似乎是无效的。'EasyMock.expect' 方法是通用的并且需要返回类型，这导致编译器告诉您不能使用 void 方法，因为它没有返回类型。
For more information, see the EasyMock API documentation at http://easymock.org/api/easymock/3.0/index.html.
有关更多信息，请参阅位于http://easymock.org/api/easymock/3.0/index.html的 EasyMock API 文档。
回答by Mike Partridge
You can't script methods with a void return in that way; check out this questionfor a good answer on how you can mock the behavior of your sendmethod on your expectedobject.
您不能以这种方式编写带有 void 返回值的方法；查看这个问题以获得关于如何send在expected对象上模拟方法行为的好答案。
