Java 从控制台读取 int
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reading int from console
提问by chatty
How can I convert a Stringarray into an intarray in java?
I am reading a stream of integer characters into a Stringarray from the console, with
java中如何将String数组转换为int数组？我正在String从控制台将整数字符流读入数组，其中
BufferedReader br = new BufferedReader (new InputStreamReader(System.in));
for(c=0;c<str.length;c++)
str[c] = br.readLine();
where str[]is String typed.
I want to compare the str[]contents ... which can't be performed on chars (the error)
And hence I want to read intfrom the console. Is this possible?
在哪里str[]输入字符串。我想比较str[]内容......不能在字符上执行（错误）因此我想int从控制台读取。这可能吗？
采纳答案by Prasoon Saurav
Integer.parseInt(String);is something that you want.
Integer.parseInt(String);是你想要的东西。
Try this:
尝试这个：
int[] array = new int[size];
try {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
for (int j = 0; j < array.length ; j++) {
int k = Integer.parseInt(br.readLine());
array[j] = k;
}
}
catch (Exception e) {
e.printStackTrace();
}
Anyways,why don't you use Scanner? It'd be much easier for you if you use Scanner. :)
无论如何，你为什么不使用扫描仪？如果您使用扫描仪，这对您来说会容易得多。:)
int[] array = new int[size];
try {
Scanner in = new Scanner(System.in); //Import java.util.Scanner for it
for (int j = 0; j < array.length ; j++) {
int k = in.nextInt();
array[j] = k;
}
}
catch (Exception e) {
e.printStackTrace();
}
回答by carillonator
int x = Integer.parseInt(String s);
回答by Rushil Paul
Using a scanner is much faster and hence more efficient. Also, it doesn't require you to get into the hassle of using buffered streams for input. Here's its usage:
使用扫描仪速度更快，因此效率更高。此外，它不需要您陷入使用缓冲流进行输入的麻烦。这是它的用法：
java.util.Scanner sc = new java.util.Scanner(System.in); // "System.in" is a stream, a String or File object could also be passed as a parameter, to take input from
int n; // take n as input or initialize it statically
int ar[] = new int[n];
for(int a=0;a<ar.length;a++)
ar[a] = sc.nextInt();
// ar[] now contains an array of n integers
Also note that, nextInt()function can throw 3 exceptions as specified here. Don't forget to handle them.
还要注意的是，nextInt()作为指定的函数可以抛出异常3这里。不要忘记处理它们。
