Python：如何将字符串转换为日期时间
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Python: How to convert string into datetime
提问by Sunny
Possible Duplicate:
Converting string into datetime
可能的重复：
将字符串转换为日期时间
I am parsing an XML file that gives me the time in the respective isoformat:
我正在解析一个 XML 文件，该文件为我提供了相应 isoformat 的时间：
tc1 = 2012-09-28T16:41:12.9976565
tc2 = 2012-09-28T23:57:44.6636597
But it is being treated as a string when I retrieve this from the XML file. I have two such time values and i need to do a diff between the two so as to find delta. But since it is a string I can not directly do tc2-tc1. But since they are already in isoformat for datetime, how do i get python to recognize it as datetime?
但是当我从 XML 文件中检索它时，它被视为一个字符串。我有两个这样的时间值，我需要在两者之间做一个差异以找到增量。但由于它是一个字符串我不能直接做 tc2-tc1。但是由于它们已经是日期时间的isoformat，我如何让python将其识别为日期时间？
thanks.
谢谢。
采纳答案by Pierre GM
Use the datetime.strptimemethod:
使用datetime.strptime方法：
import datetime
datetime.datetime.strptime(your_string, "%Y-%m-%dT%H:%M:%S.%f")
The link provided presents the different format directives. Note that the microseconds are limited to the range [0,999999], meaning that a ValueErrorwill be raised with your example (you're using 1/10us): you need to truncate your string to drop the final character.
提供的链接显示了不同的格式指令。请注意，微秒仅限于 range [0,999999]，这意味着 aValueError将在您的示例中引发（您使用的是 1/10us）：您需要截断字符串以删除最后一个字符。
回答by Sunny
Use the datetimemodule.
使用datetime模块。
td = datetime.strptime('2012-09-28T16:41:12.997656', '%Y-%m-%dT%H:%M:%S.%f') -
datetime.strptime('2012-09-28T23:57:44.663659', '%Y-%m-%dT%H:%M:%S.%f')
print td
# => datetime.timedelta(-1, 60208, 333997)
There is only one small problem: Your microseconds are one digit to long for %fto handle. So I've removed the last digits from your input strings.
只有一个小问题：你的微秒是一位%f需要处理的数字。所以我从你的输入字符串中删除了最后一位数字。
回答by Antonio Beamud
You can use the python-dateutil parse()function, it's more flexible than strptime. Hope this help you.
您可以使用python-dateutilparse()函数，它比 strptime 更灵活。希望这对你有帮助。
