javascript jQuery 选择器，包含等于
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jQuery selector, contains to equals
提问by Aharon Muallem
I have the folowing selector
我有以下选择器
var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
.find("option:contains('LIKE')");
this checks for an option which containsthe word 'like' right?
这会检查包含“喜欢”一词的选项，对吗？
How do i find an option which is exactlywith the word 'like'?
我如何找到与“喜欢”一词完全一致的选项？
Somthing like this:
像这样的东西：
var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
.find("option:equals('LIKE')");
回答by Igor Dymov
Just select all the options from the selectand filter them by text()value:
只需从 中选择所有选项select并按text()值过滤它们：
var likeComperssionOption = $('select[id*=ComparisionType]:first option').filter(function() { return $(this).text() == "LIKE" });
回答by Jon
If you want to select based on the valueattribute of the options, you need to use the attribute equals selectorto select elements with a specific value for their valueattribute:
如果要根据value选项的属性进行选择，则需要使用属性等于选择器为其value属性选择具有特定值的元素：
var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
.find("option[value='LIKE']")
Otherwise, to select based on the display text of the options, use:
否则，要根据选项的显示文本进行选择，请使用：
var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
.find("option").filter(function() {
return $(this).text() == 'LIKE';
});
Update:You might be having some problems with your initial selector, it looks very strange. You should probably change
更新：您的初始选择器可能有一些问题，看起来很奇怪。你可能应该改变
$('select[id*=ComparisionType]').eq(0)
to something simple like
一些简单的东西
$('#ComparisionType')
The concept of this answer works fine, you can see it in action here.
这个答案的概念很好用，你可以在这里看到它的实际效果。
