SQL 将日期时间转换为 Unix 时间戳
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Convert Datetime to Unix timestamp
提问by O A
In Microsoft SQL Server 2012 or above, is it possible to convert a datetime value to Unix time stamp in a single select statement? If so, how can it be done?
在 Microsoft SQL Server 2012 或更高版本中，是否可以在单个 select 语句中将日期时间值转换为 Unix 时间戳？如果是这样，怎么做？
回答by khaled4vokalz
As Peter Halasz mentions in T-SQL DateTime to Unix Timestamp:
正如 Peter Halasz 在T-SQL DateTime to Unix Timestamp 中提到的：
Converting a datetime to unix timestamp is easy, but involves error prone typing the following:
@timestamp=DATEDIFF(second,{d '1970-01-01'},@datetime)Where @datetime is the datetime value you want to convert. The {d ‘yyyy-mm-dd'} notation is an ODBC escape sequence.
The function:
CREATE FUNCTION UNIX_TIMESTAMP ( @ctimestamp datetime ) RETURNS integer AS BEGIN /* Function body */ declare @return integer SELECT @return = DATEDIFF(SECOND,{d '1970-01-01'}, @ctimestamp) return @return ENDTry it out now like below @Ousman :
SELECT UNIX_TIMESTAMP(GETDATE());
将日期时间转换为 unix 时间戳很容易，但输入以下内容很容易出错：
@timestamp=DATEDIFF(second,{d '1970-01-01'},@datetime)其中@datetime 是您要转换的日期时间值。{d 'yyyy-mm-dd'} 表示法是 ODBC 转义序列。
功能：
CREATE FUNCTION UNIX_TIMESTAMP ( @ctimestamp datetime ) RETURNS integer AS BEGIN /* Function body */ declare @return integer SELECT @return = DATEDIFF(SECOND,{d '1970-01-01'}, @ctimestamp) return @return END现在尝试一下@Ousman：
SELECT UNIX_TIMESTAMP(GETDATE());
