php 警告：fopen() [function.fopen]：文件名不能为空
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Warning: fopen() [function.fopen]: Filename cannot be empty in
提问by Ben
Im using this tutorial http://papermashup.com/caching-dynamic-php-pages-easily/for caching a page
我使用本教程http://papermashup.com/caching-dynamic-php-pages-easily/缓存页面
<?php {
$cachefile = $_SERVER['DOCUMENT_ROOT'].'cache.html';
$cachetime = 4 * 60;
// Serve from the cache if it is younger than $cachetime
if (file_exists($cachefile) && time() - $cachetime < filemtime($cachefile)) {
include($cachefile);
} else {
ob_start(); // Start the output buffer
?>
/* Heres where you put your page content */
<?php
// Cache the contents to a file
$cached = fopen($cacheFile, 'w');
fwrite($cached, ob_get_contents());
fclose($cached);
ob_end_flush(); // Send the output to the browser
}
?>
but i get the following errors
但我收到以下错误
Warning: fopen() [function.fopen]: Filename cannot be empty in
Warning: fwrite(): supplied argument is not a valid stream resource in
Warning: fclose(): supplied argument is not a valid stream resource in
The path to the file is right. And if i edit the file my self is included but again i get the errors
文件路径是对的。如果我编辑文件，我的自我被包含在内，但我再次收到错误
回答by DaveRandom
You have a problem with the casing of your variable name. PHP variable names are case sensitive. Change cacheFileto cachefile(with the small Finstead).
您的变量名的大小写有问题。PHP 变量名区分大小写。更改cacheFile为cachefile（用小F代替）。
Change this:
改变这个：
$cached = fopen($cacheFile, 'w');
To this:
对此：
$cached = fopen($cachefile, 'w');
回答by Michael Seibt
You got a spelling error: $cachefile!= $cacheFilePHP identifiers are case sensitive. So decide for one version and correct the other occurences.
您遇到拼写错误：$cachefile!= $cacheFilePHP 标识符区分大小写。所以决定一个版本并纠正其他出现的情况。
Corrected Code:
更正的代码：
$cached = fopen($cachefile, 'w');
回答by Brian Warshaw
The first time you reference $cachefile. The second time you reference $cacheFile. Fix the casing in one place or the other and you should be good.
第一次参考$cachefile。第二次参考$cacheFile。将外壳固定在一个地方或另一个地方，你应该很好。
