php 在PHP中增加日期的最简单方法？
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Simplest way to increment a date in PHP?
提问by davr
Say I have a string coming in, "2007-02-28", what's the simplest code I could write to turn that into "2007-03-01"? Right now I'm just using strtotime(), then adding 24*60*60, then using date(), but just wondering if there is a cleaner, simpler, or more clever way of doing it.
假设我输入了一个字符串"2007-02-28"，那么我可以编写的最简单的代码是"2007-03-01"什么？现在我只是使用strtotime()，然后添加24*60*60，然后使用date()，但只是想知道是否有更干净，更简单或更聪明的方法来做到这一点。
回答by ólafur Waage
A clean way isto use strtotime()
一个干净的方法是使用strtotime()
$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);
Will give you the 2007-03-01
会给你的 2007-03-01
回答by chaos
It's cleaner and simpler to add 86400. :)
添加 86400 更简洁更简单。:)
The high-tech way is to do:
高科技的方法是：
$date = new DateTime($input_date);
$date->modify('+1 day');
echo $date->format('Y-m-d');
but that's really only remotely worthwhile if you're doing, say, a sequence of transformations on the date, rather than just finding tomorrow.
但如果你在日期上进行一系列转换，而不是仅仅寻找明天，那这真的只是有点值得。
回答by Paul Dixon
You can do the addition right inside strtotime, e.g.
您可以在 strtotime 内进行添加，例如
$today="2007-02-28";
$nextday=strftime("%Y-%m-%d", strtotime("$today +1 day"));
回答by Bajlo
Another way is to use function mktime(). It is very useful function...
另一种方法是使用函数 mktime()。这是一个非常有用的功能...
$date = "2007-02-28";
list($y,$m,$d)=explode('-',$date);
$date2 = Date("Y-m-d", mktime(0,0,0,$m,$d+1,$y));
but I think strtotime()is better in that situation...
但我认为strtotime()在那种情况下更好......
回答by Biswadeep Sarkar
The simplest way...
最简单的方法...
echo date('Y-m-d',strtotime("+1 day")); //from today
OR from specified date...
或从指定日期...
echo date('Y-m-d',strtotime("+1 day", strtotime('2007-02-28')));
回答by Aominé
Hello you can try this below especially if you are french
你好，你可以在下面试试这个，特别是如果你是法国人
$date = date('l j F Y');
#increment the date
$date2 = date('l j F Y', strtotime("+7 day"));
to translate in french you can use the setlocale() function or the function below :
要翻译法语，您可以使用 setlocale() 函数或以下函数：
function fr_date($date){
$date = explode(' ', $date);
$date = str_replace('Monday','Lundi',$date);
$date = str_replace('Tuesday','Mardi',$date);
$date = str_replace('Wednesday','Mercredi',$date);
$date = str_replace('Thursday','Jeudi',$date);
$date = str_replace('Friday','Vendredi',$date);
$date = str_replace('Saturday','Samedi',$date);
$date = str_replace('Sunday','Dimanche',$date);
$date = str_replace('January','Janvier',$date);
$date = str_replace('February','Février',$date);
$date = str_replace('March','Mars',$date);
$date = str_replace('April','Avril',$date);
$date = str_replace('May','Mai',$date);
$date = str_replace('June','Juin',$date);
$date = str_replace('July','Juillet',$date);
$date = str_replace('August','Ao?t',$date);
$date = str_replace('September','Septembre',$date);
$date = str_replace('October','Octobre',$date);
$date = str_replace('November','Novembre',$date);
$date = str_replace('December','Décembre',$date);
$date = implode(' ',$date);
return $date;
}
回答by Eatsleeprace Livelife
$your_date = strtotime("1month", strtotime(date("Y-m-d")));
$new_date = date("Y-m-d", $your_date++);
回答by radhason power
$early_start_date = date2sql($_POST['early_leave_date']);
$date = new DateTime($early_start_date);
$date->modify('+1 day');
$date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
$date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);
$interval = date_diff($date_a, $date_b);
