javascript 如何使用moment.js列出2个日期之间的所有月份？
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How to list all month between 2 dates with moment.js?
提问by Tachun Lin
I've two dates
我有两个约会
2015-3-30 2013-8-31
How can I make a month list like:
我如何制作一个月的清单，例如：
[ '2015-3', '2015-2', '2015-1', '2014-12', '2014-11', '2014-10', '2014-09', '2014-08', '2014-07', '2014-06', '2014-05'....., '2013-08' ]
Thanks.
谢谢。
回答by vinjenzo
This should do it:
这应该这样做：
var dateStart = moment('2013-8-31');
var dateEnd = moment('2015-3-30');
var timeValues = [];
while (dateEnd > dateStart || dateStart.format('M') === dateEnd.format('M')) {
timeValues.push(dateStart.format('YYYY-MM'));
dateStart.add(1,'month');
}
回答by Alexander Swann
I think the original answer isn't entirely correct, as you wouldn't get '2015-3'in your array. This is due to the fact your start date would eventually end up as '2015-3-31'and would fail the conditional in place. You could extend it like below.
我认为原始答案并不完全正确，因为您不会进入'2015-3'数组。这是因为您的开始日期最终会以这样的方式结束，'2015-3-31'并且会在适当的条件下失败。你可以像下面那样扩展它。
UPDATE: I've now included cloning the dateStart variable so it isn't mutated at all.
更新：我现在已经包括克隆 dateStart 变量，因此它根本不会发生突变。
var dateStart = moment('2013-8-31');
var dateEnd = moment('2015-3-30');
var interim = dateStart.clone();
var timeValues = [];
while (dateEnd > interim || interim.format('M') === dateEnd.format('M')) {
timeValues.push(interim.format('YYYY-MM'));
interim.add(1,'month');
}
回答by Raghd Hamzeh
You are using multiple formats in the output: YYYY-MM and YYYY-M, so I picked the first. You can edit as you see fit.
您在输出中使用了多种格式：YYYY-MM 和 YYYY-M，所以我选择了第一种。您可以根据需要进行编辑。
var startDateString = "2012-5-30";
var endDateString = "2015-8-31";
var startDate = moment(startDateString, "YYYY-M-DD");
var endDate = moment(endDateString, "YYYY-M-DD").endOf("month");
var allMonthsInPeriod = [];
while (startDate.isBefore(endDate)) {
allMonthsInPeriod.push(startDate.format("YYYY-MM"));
startDate = startDate.add(1, "month");
};
console.log(allMonthsInPeriod);
document.getElementById("result").innerHTML = allMonthsInPeriod.join("<br />");<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.19.4/moment.min.js"></script>
<div id="result"></div>回答by Naing Lin Aung
You could try with this example
你可以试试这个例子
var one = moment("2015-3-30");
var two = moment("2014-8-31");
var dateDiffs = [];
var count = Math.round(moment.duration(one.diff(two)).asMonths());
month = two.month() + 1;
year = two.year();
for (var i=1; i<=count; i++) {
if (month > 12) {
month = 1;
year++;
}
dateDiffs.push(year+"-"+month);
console.log(month);
month++;
}
console.log(dateDiffs);
回答by ZEE
Why don't you just https://date-fns.org/v2.13.0/docs/eachMonthOfInterval??
你为什么不只是https://date-fns.org/v2.13.0/docs/eachMonthOfInterval？
// Each month between 6 February 2014 and 10 August 2014:
var result = eachMonthOfInterval({
start: new Date(2014, 1, 6),
end: new Date(2014, 7, 10)
})
//=> [
// Sat Feb 01 2014 00:00:00,
// Sat Mar 01 2014 00:00:00,
// Tue Apr 01 2014 00:00:00,
// Thu May 01 2014 00:00:00,
// Sun Jun 01 2014 00:00:00,
// Tue Jul 01 2014 00:00:00,
// Fri Aug 01 2014 00:00:00
// ]
