Javascript JS开关盒不起作用
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JS switch case not working
提问by Chris
I have a switch case statement that doesn't work. I've checked the input, it's valid. If user is 1, it goes to default. If user is any number, it defaults. What's wrong here? I don't know javascript well at all.
我有一个不起作用的 switch case 语句。我检查了输入，它是有效的。如果用户是 1，它会进入默认值。如果用户是任何数字，则为默认值。这里有什么问题？我根本不了解 javascript。
switch (user) {
case 1:
// stuff
break;
case 2:
// more stuff
break;
default:
// this gets called
break;
}
回答by EyalAr
Make sure you are not mixing strings and integers.
Try:
确保您没有混合字符串和整数。
尝试：
switch (user) {
case "1":
// stuff
break;
case "2":
// more stuff
break;
default:
// this gets called
}
回答by mahadeb
Problem is data type mismatch. cast type of userto integer.
问题是数据类型不匹配。将用户类型强制转换为整数。
回答by abuduba
Cast type of user variable to integer
将用户变量类型转换为整数
switch (+user) {
case 1: .. //
}
回答by disjunction
Javascript is type-aware. So '1' is not the same as 1. In your case the "user" has to be numeric, not the string. You can cast it by just:
Javascript 是类型感知的。所以 '1' 与 1 不同。在您的情况下，“用户”必须是数字，而不是字符串。您可以通过以下方式进行投射：
user = Number(user)
