java 将 JSON 发送到 Spring MVC 控制器

Question

提问by user1646481

I am trying to send JSON to a Spring MVC Controller. On the Spring MVC side, everything is configured correctly.

我正在尝试将 JSON 发送到 Spring MVC 控制器。在 Spring MVC 方面，一切都配置正确。

Below is the code but doesn't seem to run:

下面是代码，但似乎没有运行：

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>  
<script type="text/javascript">
  $('#myForm').on('submit', function(e) { 
    e.preventDefault(); 
    var frm = $("#myForm"); 
    var dat = frm.serialize(); 
    $.ajax({ 
    type: 'POST', 
    url: $('#myForm').attr('action'), 
    data: dat, 
    contentType: 'application/json' 
    success: function(hxr) { 
        alert("Success: " + xhr); 
    } 
}); 
});   
 </script>   
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/save" method="POST" accept="application/json" onclick="i()">
                <input type="text" name="name" value="myName">
    <input type="submit" value="Submit">
</form>

In Tomcat I get the following error:

在Tomcat中，我收到以下错误：

org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod WARNING: No matching handler method found for servlet request: path '/application/save', method 'POST', parameters map['name' -> array['myName']]

org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod 警告：找不到与 servlet 请求匹配的处理程序方法：路径 '/application/save'，方法 'POST'，参数 map['name' -> array['我的名字']]

Any ideas where I am going wrong? I am new to JSON. I am trying to to send JSON to Spring MVC controller.

我哪里出错了？我是 JSON 的新手。我正在尝试将 JSON 发送到 Spring MVC 控制器。

@Controller
@RequestMapping("/run/*")
public class HistoryController {

    @RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody Response save(@RequestBody User user) throws Exception {
    Response userResponse = new Response();
    System.out.println("UserId :" + " " + user.getName());
    return userResponse;
}
}

@RequestMapping(value = "find", method = RequestMethod.GET)
public @ResponseBody Response find() {
    System.out.println("Run");
    Response userResponse = new Response();
    userResponse.setVersionNumber("1.0");
    return userResponse;
}

When invoking /application/run/save I get a JSON response. However the @RequestBody does not work.

调用 /application/run/save 时，我得到一个 JSON 响应。但是@RequestBody 不起作用。

I still have had no luck. Have read some many similiar problems. The requirement is that the server will only accept application/json types. I am using a Spring MVC Controller. As mentioned earlier, the code sends a response back as JSON through @ResponseBody. I want to get information through the @RequestBody in my Spring MVC Controller. I am using JSP to send JSON to Spring MVC Controller. My code and Spring MVC can be seen below:

我仍然没有运气。已经阅读了许多类似的问题。要求是服务器只接受 application/json 类型。我正在使用 Spring MVC 控制器。如前所述，代码通过@ResponseBody 将响应作为 JSON 发送回。我想通过我的 Spring MVC 控制器中的 @RequestBody 获取信息。我正在使用 JSP 将 JSON 发送到 Spring MVC 控制器。我的代码和 Spring MVC 如下所示：

I am new to JSON and Javascript.

我是 JSON 和 Javascript 的新手。

JSP - index.jsp

<%@page language="java" contentType="text/html"%>
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>  
<script type="text/javascript">
    $('#myForm').on('submit', function(e) { 
    var frm = $("#myForm");
   var dat = JSON.stringify(frm.serializeArray()); 

$.ajax({ 
     type: 'POST', 
     url: $('#myForm').attr('action'), 
     data: dat,
     contentType: 'application/json',
     dataType: 'json',
     error: function() {
        alert('failure');
     }
     success: function(hxr) { 
         alert("Success: " + xhr); 
     }
  }); 
); 
}; 
</script> 
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/save" method="POST" accept="application/json" onclick="i()">
    <input type="text" name="userId" value="User">
    <input type="submit" value="Submit">
</form>
</body>
</html>

When running this I am not getting any output. In the Chrome I get 404 Not found error and in Tomcat I get the following error:

运行它时，我没有得到任何输出。在 Chrome 中，我收到 404 Not found 错误，在 Tomcat 中我收到以下错误：

org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver     handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/application/sa
 ve', method 'POST', parameters map['userId' -> array<String>['User']]

Is something wrong here in the JSP part?

JSP 部分有什么问题吗？

web.xml

网页.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd"
     version="2.5">

     <display-name>WebApp</display-name>

     <context-param>
        <!-- Specifies the list of Spring Configuration files in comma separated format.-->
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/service.xml</param-value>
     </context-param>

     <listener>
        <!-- Loads your Configuration Files-->
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
     </listener>

     <servlet>
        <servlet-name>application</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
     </servlet>

     <servlet-mapping>
        <servlet-name>application</servlet-name>
        <url-pattern>/</url-pattern>
     </servlet-mapping>

     <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
     </welcome-file-list>    
</web-app>

service.xml

服务.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
    http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.0.xsd">

    <context:component-scan base-package="com.web"/>

    <mvc:annotation-driven/>

    <context:annotation-config/>

    <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/>

    <bean id="HymansonMessageChanger" class="org.springframework.http.converter.json.MappingHymansonHttpMessageConverter">
        <property name="supportedMediaTypes" value="application/json"/>
    </bean>

    <!-- <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
        <property name="messageConverters">
            <list>
                <ref bean="HymansonMessageChanger"/>
            </list>
        </property>
    </bean>-->

    <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
        <property name="messageConverters">
            <util:list id="beanList">
                <ref bean="HymansonMessageChanger"/>
            </util:list>
        </property>
    </bean>

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/jsp/"/>
        <property name="suffix" value=".jsp"/>
    </bean>

    <!-- <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
        <property name="mediaTypes">
            <map>
                <entry key="json" value="application/json"/>
            </map>
        </property>
    </bean>-->  
</beans>

Controller

控制器

package com.web;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RequestBody;
import com.webchannel.domain.User;
import com.webchannel.domain.UserResponse;

@Controller
@RequestMapping("/application/*")
public class SaveController {

@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody UserResponse save(@RequestBody User user) throws Exception {
    UserResponse userResponse = new UserResponse();
    System.out.println("UserId :" + " " + user.getUserId());
    return userResponse;
}

@RequestMapping(value = "delete", method = RequestMethod.GET)
public @ResponseBody UserResponse delete() {
    System.out.println("Delete");
    UserResponse userResponse = new UserResponse();
    userResponse.setSuccess(true);
    userResponse.setVersionNumber("1.0");
    return userResponse;
}
}

When invoking /application/delete I get JSON returned. So I know my HymansonProcessor is configured correctly. The problem is in @RequestBody.

调用 /application/delete 时，返回 JSON。所以我知道我的 HymansonProcessor 配置正确。问题出在@RequestBody 中。

Where am I going wrong? Please help me.

我哪里错了？请帮我。

Answer 1

回答by matt b

This question is a bit hard to follow since there seems to be a few different problems.

这个问题有点难以理解，因为似乎有几个不同的问题。

But looking just at this problem:

但看看这个问题：

In Tomcat I get the following error:
org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod WARNING: No matching handler method found for servlet request: path '/application/run', method 'POST', parameters map['name' -> array['myName']]

在Tomcat中，我收到以下错误：
org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod 警告：找不到与 servlet 请求匹配的处理程序方法：路径 '/application/run'，方法 'POST'，参数映射 ['name' -> array['我的名字']]

In the HTML you posted, you have a <form>that is set to POSTto /application/run.

在您发布的 HTML 中，您将<form>设置POST为/application/run。

However, in your @Controllerclass, you do not have any method bound to this URL.

但是，在您的@Controller类中，您没有绑定到此 URL 的任何方法。

Because you've annotated the class with @RequestMapping("/run/*")and the method is annotated with @RequestMapping("save"), the save()method is actually bound to the URL /run/save- which is neither the URL you are sending data to with $.ajax()nor the URL the form is pointing at.

因为您已经用注释了该类@RequestMapping("/run/*")并且该方法被注释为@RequestMapping("save")，所以该save()方法实际上绑定到 URL /run/save- 这既不是您发送数据所用$.ajax()的 URL ，也不是表单指向的 URL。

I would suggest turning up logging on the org.springframework.webloggers to DEBUG- when your app starts up Spring will log every URL that each method is mapped to.

我建议打开记录org.springframework.web器的日志记录DEBUG- 当您的应用程序启动时，Spring 将记录每个方法映射到的每个 URL。

Answer 2

回答by raddykrish

I think you may need make couple of changes

我认为您可能需要进行一些更改

Since your controller has @RequestMapping("/run/*"), you may need to change this to @RequestMapping("/run/")and in the jsp form action you may need to change <form id="myForm" action="/application/run/save" method="POST" accept="application/json" onclick="i()">, since you have defined @RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})for the 'save` method in the controller.
You may need to define the @RequestParam in the save method in controller like public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody User user) throws Exception {...}

由于您的控制器具有@RequestMapping("/run/*")，您可能需要将其更改为@RequestMapping("/run/")并且在您可能需要更改的 jsp 表单操作中<form id="myForm" action="/application/run/save" method="POST" accept="application/json" onclick="i()">，因为您已经@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})在控制器中定义了 'save` 方法。
您可能需要在控制器的 save 方法中定义@RequestParam，例如 public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody User user) throws Exception {...}

Since it clearly says that there is no handler attached to the request you are submitting.

因为它清楚地表明您提交的请求没有附加处理程序。

Answer 3

回答by Mat

There is no method in the controller mapped to your /application/run. I'm not sure which one you want to call, but to the urlyou have to add findorsave. Or create a method mapped to /application/run. Cheers!

控制器中没有方法映射到您的/application/run. 我不确定你想打电话给哪个，但url你必须添加find或save。或者创建一个映射到/application/run. 干杯!

Answer 4

回答by code-jaff

Try the following

尝试以下

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>  
<script type="text/javascript">
$('#myForm').on('submit', function(e) {
    e.preventDefault();
    var frm = $("#myForm");
    var dat = frm.serialize();
    $.ajax({
        type: 'POST',
        url: $('#myForm').attr('action'),
        data: dat,
        contentType: 'application/json'
        success: function(hxr) {
            alert("Success: " + hxr);
        }
    });
});    
</script>   
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/run" method="POST">
    <input type="text" name="name" value="myName">
    <input type="submit" value="Submit">
</form>?

The dataType:'json'is specifying what the format you are expecting from the server,

在dataType:'json'被指定是什么格式，你从服务器期待，

And it would be better to assist if you post your handler code.

如果您发布处理程序代码，最好提供帮助。

java 将 JSON 发送到 Spring MVC 控制器

提问by user1646481

回答by matt b

回答by raddykrish

回答by Mat

回答by code-jaff

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java 将 JSON 发送到 Spring MVC 控制器

提问by user1646481

回答by matt b

回答by raddykrish

回答by Mat

回答by code-jaff

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