java.time.format.DateTimeParseException：无法在索引 21 处解析文本
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java.time.format.DateTimeParseException: Text could not be parsed at index 21
提问by daydreamer
I get the datetime value as
我得到日期时间值
created_at '2012-02-22T02:06:58.147Z'
Read-only. The time at which this task was created.
Which is given by Asana API
由 Asana API 提供
I am using Java 8to parse the date time as following
我Java 8用来解析日期时间如下
import java.time.*;
import java.time.format.*;
public class Times {
public static void main(String[] args) {
final String dateTime = "2012-02-22T02:06:58.147Z";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'hh:mm:ss.SX");
final ZonedDateTime parsed = ZonedDateTime.parse(dateTime, formatter);
System.out.println(parsed);
}
}
When I run this, I get the following error
当我运行它时，我收到以下错误
Exception in thread "main" java.time.format.DateTimeParseException: Text '2012-02-22T02:06:58.147Z' could not be parsed at index 21
at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1947)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1849)
at java.time.ZonedDateTime.parse(ZonedDateTime.java:597)
at Times.main(Times.java:11)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:140)
What is not right here?
这里有什么不对？
采纳答案by assylias
The default parser can parse your input. So you don't need a custom formatter and
默认解析器可以解析您的输入。所以你不需要自定义格式化程序和
String dateTime = "2012-02-22T02:06:58.147Z";
ZonedDateTime d = ZonedDateTime.parse(dateTime);
works as expected.
按预期工作。
回答by daydreamer
The following worked for me
以下对我有用
import java.time.*;
import java.time.format.*;
public class Times {
public static void main(String[] args) {
final String dateTime = "2012-02-22T02:06:58.147Z";
DateTimeFormatter formatter = DateTimeFormatter.ISO_INSTANT;
final ZonedDateTime parsed = ZonedDateTime.parse(dateTime, formatter.withZone(ZoneId.of("UTC")));
System.out.println(parsed.toLocalDateTime());
}
}
and gave me output as
并给了我输出
2012-02-22T02:06:58.147
回答by Meno Hochschild
Your original problem was wrong pattern symbol "h" which stands for the clock hour (range 1-12). In this case, the am-pm-information is missing. Better, use the pattern symbol "H"instead (hour of day in range 0-23). So the pattern should rather have been like:
您最初的问题是错误的模式符号“h”，它代表时钟小时（范围 1-12）。在这种情况下，缺少 am-pm-information。更好的是，使用模式符号“H”代替（一天中的小时在 0-23 范围内）。所以模式应该是这样的：
uuuu-MM-dd'T'HH:mm:ss.SSSX (best pattern also suitable for strict mode)
uuuu-MM-dd'T'HH:mm:ss.SSSX（最好的模式也适用于严格模式）
回答by Roman
If your input always has a time zone of "zulu" ("Z" = UTC), then you can use DateTimeFormatter.ISO_INSTANT(implicitly):
如果您的输入始终具有“zulu”（“Z”= UTC）的时区，那么您可以使用DateTimeFormatter.ISO_INSTANT（隐式）：
final Instant parsed = Instant.parse(dateTime);
If time zone varies and has the form of "+01:00" or "+01:00:00" (when not "Z"), then you can use DateTimeFormatter.ISO_OFFSET_DATE_TIME:
如果时区变化并且具有“+01:00”或“+01:00:00”的形式（当不是“Z”时），那么您可以使用DateTimeFormatter.ISO_OFFSET_DATE_TIME：
DateTimeFormatter formatter = DateTimeFormatter.ISO_OFFSET_DATE_TIME;
final ZonedDateTime parsed = ZonedDateTime.parse(dateTime, formatter);
If neither is the case, you can construct a DateTimeFormatterin the same manner as DateTimeFormatter.ISO_OFFSET_DATE_TIMEis constructed.
如果两者都不是，您可以DateTimeFormatter按照与DateTimeFormatter.ISO_OFFSET_DATE_TIME构造相同的方式构造 a 。
Your current pattern has several problems:
您当前的模式有几个问题：
- not using strict mode (
ResolverStyle.STRICT); - using
yyyyinstead ofuuuu(yyyywill not work in strict mode); - using 12-hour
hhinstead of 24-hourHH; - using only one digit
Sfor fractional seconds, but input has three.
- 不使用严格模式（
ResolverStyle.STRICT）； - 使用
yyyy而不是uuuu（yyyy在严格模式下不起作用）； - 使用 12 小时
hh而不是 24 小时HH； S小数秒只使用一位，但输入有三位。
