Java 字符串数组初始化作为构造函数参数
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String array initialization as constructor parameter
提问by Hermann Hans
In Java, it is completely legal to initialize a String array in the following way:
在 Java 中，通过以下方式初始化 String 数组是完全合法的：
String[] s = {"FOO", "BAR"};
However, when trying to instantiate a class that takes a String array as a parameter, the following piece of code is NOT allowed:
但是，当尝试实例化一个将 String 数组作为参数的类时，不允许使用以下代码：
Test t = new Test({"test"});
But this works again:
但这又奏效了：
Test t = new Test(new String[] {"test"});
Can someone explain why this is?
有人可以解释为什么会这样吗？
采纳答案by Jigar Joshi
String[] s = {"FOO", "BAR"};
this is allowed at declaration time only
这仅在声明时允许
You can't
你不能
String[] s;
s={"FOO", "BAR"};
回答by Karl Knechtel
Because Type[] x = { ... }is an initializationsyntax for arrays. The { ... }is interpreted in a specific way only in that specific context.
因为Type[] x = { ... }是数组的初始化语法。将{ ... }仅在特定语境解释以特定的方式。
回答by Peter Lawrey
For you want a simple way to pass a String array, I suggest you use varargs
如果你想要一个简单的方法来传递一个 String 数组，我建议你使用 varargs
class Test {
public Test(String...args);
}
// same as new Test(new String[] { "test", "one" })
Test t = new Test("test", "one");
