MySQL 在数据库中存储标签的最佳实践?
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Best practice for storing tags in a database?
提问by John Dewans
I developed a site that uses tags (key words) in order to categorize photographs. Right now, what I have in my MySQL database is a table with the following structure:
我开发了一个使用标签(关键词)来分类照片的网站。现在,我的 MySQL 数据库中有一个具有以下结构的表:
image_id (int)
tag (varchar(32))
Every time someone tags an image (if the tag is valid and has enough votes) it's added to the database. I think that this isn't the optimal way of doing things since now that I have 5000+ images with tags, the tags table has over 40000 entries. I fear that this will begin to affect performance (if it's not already affecting it).
每次有人标记图像时(如果标记有效并且有足够的票数),它就会被添加到数据库中。我认为这不是最佳的做事方式,因为现在我有 5000 多张带标签的图像,标签表有超过 40000 个条目。我担心这会开始影响性能(如果它还没有影响它的话)。
I considered this other structure thinking that it'd be faster to fetch the tags associated to a particular image but then it looks horrible for when I want to get all the tags, or the most popular one for instance:
我考虑过另一种结构,认为获取与特定图像关联的标签会更快,但是当我想要获取所有标签或最受欢迎的标签时,它看起来很糟糕,例如:
image_id (int)
tags (text) //comma delimited list of tags for the image
Is there a correct way of doing this or are both ways more or less the same? Thoughts?
是否有正确的方法来做到这一点,或者两种方式或多或少相同?想法?
回答by OMG Ponies
Use a many-to-many table to link a TAG
record to an IMAGE
record:
使用多对多表将TAG
记录链接到IMAGE
记录:
IMAGE
图片
DROP TABLE IF EXISTS `example`.`image`;
CREATE TABLE `example`.`image` (
`image_id` int(10) unsigned NOT NULL auto_increment,
PRIMARY KEY (`image_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
TAG
标签
DROP TABLE IF EXISTS `example`.`tag`;
CREATE TABLE `example`.`tag` (
`tag_id` int(10) unsigned NOT NULL auto_increment,
`description` varchar(45) NOT NULL default '',
PRIMARY KEY (`tag_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
IMAGE_TAG_MAP
IMAGE_TAG_MAP
DROP TABLE IF EXISTS `example`.`image_tag_map`;
CREATE TABLE `example`.`image_tag_map` (
`image_id` int(10) unsigned NOT NULL default '0',
`tag_id` int(10) unsigned NOT NULL default '0',
PRIMARY KEY (`image_id`,`tag_id`),
KEY `tag_fk` (`tag_id`),
CONSTRAINT `image_fk` FOREIGN KEY (`image_id`) REFERENCES `image` (`image_id`),
CONSTRAINT `tag_fk` FOREIGN KEY (`tag_id`) REFERENCES `tag` (`tag_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
回答by Dalius ?idlauskas
In multi tag search query you will have to hit every tag that is requested. Hence image tag set Ihas to be a superset of the request tag set U.
在多标签搜索查询中,您必须点击请求的每个标签。因此图像标签集I必须是请求标签集U的超集。
I >= U
To implement this complex comparison in SQL is a bit of challenge as each of the image has to be qualified individually. Given that tags are unique set per image:
在 SQL 中实现这种复杂的比较有点挑战,因为每个图像都必须单独进行限定。鉴于每个图像的标签是唯一的:
SELECT i.* FROM images AS i WHERE {n} = (
SELECT COUNT(*)
FROM image_tags AS t
WHERE t.image_id = i.image_id
AND t.tag IN ({tag1}, {tag2}, ... {tagn})
)
Schema:
架构:
CREATE TABLE images (
image_id varchar NOT NULL,
PRIMARY KEY (image_id)
)
CREATE TABLE image_tags (
image_id varchar NOT NULL,
tag varchar NOT NULL,
PRIMARY KEY (image_id, tag)
)
回答by Matt Williamson
You can make a tags
table which is just an id
and tag
with a unique constraint on tag
and then photo_tags
table which has tag_id
and photo_id
. Insert a tag into the tags
table only if it doesn't already exist.
您可以制作一个tags
表,它只是一个id
and 并且tag
具有唯一约束tag
,然后photo_tags
是具有tag_id
and 的表photo_id
。tags
仅当标签不存在时才将标签插入表中。
Then you will be querying by a pk instead of varchar text comparison when doing queries like how many photos are tagged with a certain tag.
然后,在执行诸如使用某个标签标记了多少张照片之类的查询时,您将通过 pk 而不是 varchar 文本比较进行查询。