php Laravel 不同计数

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时间:2020-08-26 00:36:47  来源:igfitidea点击:

Laravel Distinct Count

phpdatabaselaraveleloquent

提问by saimcan

Any way to make this query work using laravel? DB::raw or Eloquent usage doesn't matter.

有什么办法可以让这个查询使用 laravel 工作吗?DB::raw 或 Eloquent 的用法无关紧要。

SELECT count(DISTINCT name) FROM tablename;

Here's what i've tried but cannot get the proper output:

这是我尝试过但无法获得正确输出的内容:

EloquentTableName::select(DB::raw('count(DISTINCT name) as name_count'))->get();

This returns something like this and i'd like to fix that:

这会返回这样的东西,我想解决这个问题:

([{"name_count":"15"}])

I just want to get count 15.

我只想数到 15。

回答by Gouda Elalfy

you can simply replace get with count in this way:

您可以通过这种方式简单地将 get 替换为 count :

$count = DB::table('tablename')->count(DB::raw('DISTINCT name'));

also can do:

还可以:

DB::table('tablename')->distinct('name')->count('name');

回答by Alisha Lamichhane

You may simply do the following:

您可以简单地执行以下操作:

Tablename::distinct()->count('name');

回答by Chandan Mistry

DB::table('tablename')->distinct()->count('name');

is the correct answer.

是正确答案。

->distinct('name')does notwork in Laravel.

- >不同的(“名称”)工作Laravel。

回答by Laerte

Try this:

尝试这个:

$result = TableName::groupBy('name')->count();

Hope it helps...

希望能帮助到你...