如何访问在 PHP 多选下拉列表中选择的值?

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时间:2020-08-25 05:28:40  来源:igfitidea点击:

How to access the values selected in the multiselect dropdown list in PHP?

phpmulti-select

提问by Allen

I am using Jquery Multiselect Widgetto have a dropdown list box with mulitselect option. I am populating the dropdown with the data from MySql database. I was not able to pass multiple values to the php file in $_POST.

我正在使用Jquery Multiselect Widget来创建一个带有 multiselect 选项的下拉列表框。我正在用 MySql 数据库中的数据填充下拉列表。我无法在 $_POST 中将多个值传递给 php 文件。

My HTML & PHP code for Multiselect DropDown.

我的多选下拉菜单的 HTML 和 PHP 代码。

   <form id="intermediate" name="inputMachine" method="post">

<select id="selectDuration" name="selectDuration" multiple="multiple"> 
  <option value="1 WEEK" >Last 1 Week</option>
  <option value="2 WEEK" >Last 2 Week </option>
  <option value="3 WEEK" >Last 3 Week</option>
</select>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;


    <?php
        //include '../db/interface/DB_Manager.php';
        $connect = mysql_connect("localhost", "root", "infinit") or die(mysql_error()); 
        mysql_select_db("serverapp") or die(mysql_error()); 

        $query = "select id,name from rpt_shift_def"; //Write a query
        $data = mysql_query($query);  //Execute the query
    ?>
    <select id="selectShift" name="selectShift" multiple="multiple">
    <?php
    while($fetch_options = mysql_fetch_array($data)) { //Loop all the options retrieved from the query
    ?>

    <option name="selected_ids[]" id ="<?php echo $fetch_options['id']; ?>"  value="<?php echo $fetch_options['name']; ?>"><?php echo $fetch_options['name']; ?></option><!--Echo out options-->
    <?php
        }
    ?>
    </select>

Here i'm populating Shift dropdown in Multiselect Dropdown. If i select more than one shift, i was not able to get all those selected values in php. instead i get only the last selected value.

在这里,我在多选下拉列表中填充 Shift 下拉列表。如果我选择了多个班次,我将无法在 php 中获得所有这些选定的值。相反,我只得到最后选择的值。

i want to do something like this.

我想做这样的事情。

   $shiftarraycalc = array();

foreach ($_POST['selectShift'] as $key => $value) {
    array_push($shiftarraycalc,$value);
}

but its not working.

但它不工作。

I have no idea how to get multiple values in $_POST.

我不知道如何在 $_POST 中获取多个值。

回答by Allen

Modified name as array in select

修改名称为选择中的数组

<select id="selectShift" name="selectShift[]" multiple="multiple">

and did like this and it works

并且这样做了并且它有效

$shiftarraycalc = array();
$shift=$_POST['selectShift'];

if ($shift)
{
    foreach ($shift as $value)
    {
        array_push($shiftarraycalc,$value);
    }
}

回答by Dulith De Costa

You could do like this too.

你也可以这样做。

<form action="ResultsDulith.php" id="intermediate" name="inputMachine[]" multiple="multiple" method="post">
    <select id="selectDuration" name="selectDuration[]" multiple="multiple"> 
        <option value="1 WEEK" >Last 1 Week</option>
        <option value="2 WEEK" >Last 2 Week </option>
        <option value="3 WEEK" >Last 3 Week</option>
         <option value="4 WEEK" >Last 4 Week</option>
          <option value="5 WEEK" >Last 5 Week</option>
           <option value="6 WEEK" >Last 6 Week</option>
    </select>
     <input type="submit"/> 
</form>

Then take the multiple selection from following PHPcode below. It print the selected multiple values accordingly.

然后从下面的PHP代码中进行多项选择。它相应地打印选定的多个值。

$shift=$_POST['selectDuration'];

print_r($shift);

回答by hanuman kumar

<select id="hanu" name="hanu[]" multiple="multiple">
<option> one</option>
<option> two </option>
<option> three</option>
<option> four </option>
<option> five</option>
<option> six </option>
<option> seven</option>
</select>`

And The php code for this is

而这个 php 代码是

$res_hanu = array();
$hanu_new=$_POST['hanu'];
if ($hanu_new){
foreach ($hanu_new as $value){
array_push($res_hanu,$value);
}
}

回答by aftab

$shift=$_POST['selectShift'];

if ($shift)
{
    foreach ($shift as $value)
    {
        $shiftarraycalc[]=$value;
    }
}