在 C# 中将整数添加到字符串
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Adding integers to strings in C#
提问by A.R.
Recently I have been informed that it is possible to concatenate integers (and other types) to string and vice versa, i.e.
最近我被告知可以将整数（和其他类型）连接到字符串，反之亦然，即
// x == "1234"
// y == "7890"
string x = "123" + 4;
string y = 7 + "890";
For some reason I didn't think this kind of thing was allowed, so I have always been using (since .NET 2) the form:
出于某种原因，我认为这种事情是不允许的，所以我一直在使用（自 .NET 2 起）以下形式：
// x == "1234"
// y == "7890"
string x = "123" + 4.ToString();
string y = 7.ToString() + "890";
where the integers are converted to strings. Has the former version always been available, and I've missed it, or is it something that is new to C# 4 (which is what I am using now)?
其中整数转换为字符串。以前的版本是否一直可用，我错过了它，还是它是 C# 4 的新版本（我现在正在使用它）？
采纳答案by BrokenGlass
This has always been there. The +is equivalent to string.Concat()if at least one of the operands is a string. string.Concat()has an overload that takes an objectinstance. Internally it will call the object's ToString()method before concatenating.
这一直存在。的+相当于string.Concat()如果操作数中的至少一个是一个字符串。string.Concat()有一个带object实例的重载。在内部，它将ToString()在连接之前调用对象的方法。
Found the relevant section in the C# spec - section 7.7.4 Addition operator:
在 C# 规范中找到相关部分 - 第 7.7.4 节加法运算符：
String concatenation:
string operator +(string x, string y); string operator +(string x, object y); string operator +(object x, string y);The binary + operator performs string concatenation when one or both operands are of type string. If an operand of string concatenation is null, an empty string is substituted. Otherwise, any non-string argument is converted to its string representation by invoking the virtual ToString method inherited from type object. If ToString returns null, an empty string is substituted.
字符串连接：
string operator +(string x, string y); string operator +(string x, object y); string operator +(object x, string y);当一个或两个操作数都是字符串类型时，二元 + 运算符执行字符串连接。如果字符串连接的操作数为空，则替换为空字符串。否则，通过调用从类型对象继承的虚拟 ToString 方法，将任何非字符串参数转换为其字符串表示形式。如果 ToString 返回 null，则替换为空字符串。
回答by Joe
Of course, the best answer is to use some form of:
当然，最好的答案是使用某种形式：
String.Format("{0},{1}", "123", 4);
