Java AES 256 加密
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Java AES 256 encryption
提问by rupen
I have the below java code to encrypt a string which uses a 64 character key. My question is will this be a AES-256 encryption?
我有以下 java 代码来加密使用 64 个字符的密钥的字符串。我的问题是这会是 AES-256 加密吗？
String keyString = "C0BAE23DF8B51807B3E17D21925FADF273A70181E1D81B8EDE6C76A5C1F1716E";
byte[] keyValue = hexStringToByte(keyString);
Key key = new SecretKeySpec(keyValue, "AES");
Cipher c1 = Cipher.getInstance("AES");
c1.init(Cipher.ENCRYPT_MODE, key);
String data = "Some data to encrypt";
byte[] encVal = c1.doFinal(data.getBytes());
String encryptedValue = Base64.encodeBase64String(encVal);
/* Copied the below code from another post in stackexchange */
public static byte[] hexStringToByte(String hexstr)
{
byte[] retVal = new BigInteger(hexstr, 16).toByteArray();
if (retVal[0] == 0)
{
byte[] newArray = new byte[retVal.length - 1];
System.arraycopy(retVal, 1, newArray, 0, newArray.length);
return newArray;
}
return retVal;
}
The following is the code after incorporating suggestions from divanov and laz.
以下是合并了 divanov 和 laz 的建议后的代码。
String keyString = "C0BAE23DF8B51807B3E17D21925FADF273A70181E1D81B8EDE6C76A5C1F1716E";
byte[] keyValue = DatatypeConverter.parseHexBinary(keyString);
Key key = new SecretKeySpec(keyValue, "AES");
Cipher c1 = Cipher.getInstance("AES");
c1.init(Cipher.ENCRYPT_MODE, key);
String data = "Some data to encrypt";
byte[] encVal = c1.doFinal(data.getBytes());
String encryptedValue = Base64.encodeBase64String(encVal);
采纳答案by divanov
Yes, it will as 64 characters are 32 bytes and 256 bits and any sequence of 256 bits can be used as an AES-256 key.
是的，因为 64 个字符是 32 字节和 256 位，任何 256 位序列都可以用作 AES-256 密钥。
I suggest you to use DatatypeConverter.parseHexBinary(or similar utility from library of your choice) to convert hexadecimal strings into byte arrays.
我建议您使用DatatypeConverter.parseHexBinary（或您选择的库中的类似实用程序）将十六进制字符串转换为字节数组。
