如何在 Java 中用前导空格格式化数字
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How to format numbers with leading spaces in Java
提问by user3437460
I have the following Java codes to generate numbers padded by zeroes.
我有以下 Java 代码来生成用零填充的数字。
DecimalFormat fmt = new DecimalFormat("000");
for (int y=1; y<12; y++)
{
System.out.print(fmt.format(y) + " ");
}
The output is as follows:
输出如下：
001 002 003 004 005 006 007 008 009 010 011
001 002 003 004 005 006 007 008 009 010 011
My question is: how do I generate numbers with padded spaces instead of leading zeroes?
我的问题是：如何生成带有填充空格而不是前导零的数字？
1 2 3 4 5 6 7 8 9 10 11
1 2 3 4 5 6 7 8 9 10 11
Note: I know there are several quesitons achieved in StackOverflow asking for padding spaces in String. I know how to do it with String. I am asking is it possible to format NUMBERSwith padded space?
注意：我知道在 StackOverflow 中有几个问题要求在 String 中填充空格。我知道如何用 String 做到这一点。我问是否可以用填充空间格式化NUMBERS？
采纳答案by Raul Guiu
for (int y=1; y<12; y++)
{
System.out.print(String.format("%1s", y));
}
It will print Strings of length 4, so if y=1 it will print 3 spaces and 1, " 1", if y is 10 it will print 2 spaces and 10, " 10"
它将打印长度为 4 的字符串，因此如果 y=1 它将打印 3 个空格和 1, " 1"，如果 y 是 10 它将打印 2 个空格和 10, " 10"
回答by user176692
int i = 0;
while (i < 12) {
System.out.printf("%4d", i);
++i;
}
The 4 is the width. You could also replace printf with format.
4 是宽度。您也可以用格式替换 printf 。
