xcode C++，构造函数：“类”的外定义与“类”中的任何声明都不匹配
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C++, Constructors: Out-of-line definition of 'class' does not match any declaration in 'class'
提问by bughHD
So I was trying to program a target heart rate calculator in C++ and when I tried to build it, this error was returned. Just to let you know, I am instructed to separate the implementation and interface.
所以我试图用 C++ 编写一个目标心率计算器，当我尝试构建它时，返回了这个错误。只是为了让您知道，我被指示将实现和接口分开。
Here's the interface
这是界面
#include <iostream>
#include <string>
class HeartRates
{
public:
// constructor initialize HeartRates
HeartRates( std::string, std::string, int, int, int );
// Setting each variable
void setFirstName( std::string );
void setLastName( std::string );
void setdobMonth( int );
void setdobDay( int );
void setdobYear( int );
void setCurrentYear( int );
std::string getFirstName() const;
std::string getLastName() const;
int getdobMonth() const;
int getdobDay() const;
int getdobYear() const;
int getCYear() const;
int getAge() const;
int getMaximumHeartRate() const;
int getTargetHeartRate() const;
private:
std::string firstName;
std::string lastName;
int dobMonth;
int dobDay;
int dobYear;
int currentYear;
};
And here's the implementation
这是实现
#include <iostream>
#include <string>
#include "HeartRates.h"
using namespace std;
// constructor that initializes all the stuff
This is the line that is giving me this error: Out-of-line definition of 'HeartRates' does not match any declaration in 'HeartRates'
这是给我这个错误的行：“HeartRates”的线外定义与“HeartRates”中的任何声明都不匹配
HeartRates::HeartRates( string first, string last, int M, int D, int Y, int cY )
{
setFirstName( first );
setLastName( last );
setdobMonth( M );
setdobDay( D );
setdobYear( Y );
setCurrentYear( cY );
}
Continue on with the code
继续看代码
// set functions
void HeartRates::setFirstName( string first )
{
firstName = first; // store the first name in the object
}
void HeartRates::setLastName( string last )
{
lastName = last; // store the last name in the object
}
void HeartRates::setdobMonth( int M )
{
dobMonth = M; // store the month of birth in the object
}
void HeartRates::setdobDay( int D )
{
dobDay = D; // store the day of birth in the object
}
void HeartRates::setdobYear( int Y )
{
dobYear = Y; // store the year of birth in the object
}
void HeartRates::setCurrentYear( int cY )
{
currentYear = cY;
}
// get functions
string HeartRates::getFirstName() const
{
return firstName; // return user's first name
}
string HeartRates::getLastName() const
{
return lastName; // return user's last name
}
int HeartRates::getdobMonth() const
{
return dobMonth;
}
int HeartRates::getdobDay() const
{
return dobDay;
}
int HeartRates::getdobYear() const
{
return dobYear;
}
int HeartRates::getCYear() const
{
return currentYear;
}
// Functions
int HeartRates::getAge() const
{
int age;
age = currentYear-dobYear;
return age;
}
int HeartRates::getMaximumHeartRate() const
{
int maxHeartRate;
maxHeartRate = 220 - getAge();
return maxHeartRate;
}
int HeartRates::getTargetHeartRate() const
{
int targetHeartRate;
targetHeartRate = getMaximumHeartRate() * 0.85;
return targetHeartRate;
}
Sorry for the formatting and copy and pasting everything. Newbie here, I just don't know which part of the code went wrong.
抱歉格式化并复制和粘贴所有内容。这里的新手，我只是不知道代码的哪一部分出错了。
回答by Yudaev Alexander
HeartRates( std::string, std::string, int, int, int );
2 strings and 3 int.
2 个字符串和 3 个整数。
HeartRates::HeartRates( string first, string last, int M, int D, int Y, int cY )
2 strings and 4 int.
2 个字符串和 4 个整数。
回答by Mike
I had a similar issue today and my fix was slightly different, so I'll throw this here in case it ever helps anyone in the future. I had forward declared a class OUTSIDE of the appropriate namespace in the header, so my error looked something like this:
我今天遇到了类似的问题，我的修复略有不同，所以我会把它扔在这里，以防它将来对任何人有帮助。我在头文件中预先声明了一个适当命名空间的 OUTSIDE 类，所以我的错误看起来像这样：
1. Type of 1st parameter of member declaration does not match definition
'const std::shared_ptr<MyClass> &' (aka 'const shared_ptr<MyClass> &') vs
'const std::shared_ptr<MyClass> &' (aka 'const shared_ptr<myNamespace::MyClass> &'))
The solution for me was to forward declare that class inside the namespace, rather than outside it.
我的解决方案是在名称空间内而不是在名称空间外转发声明该类。
Bad:
坏的：
class MyClass;
namespace myNamespace {
}
Good:
好的：
namespace myNamespace {
class MyClass;
}
