如何确定值是否是 PHP 中的日期
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How to determine if value is a date in PHP
提问by Todd Moses
I am working with arrays of values in PHP. Some of these values may include a date in various string formats.
我正在处理 PHP 中的值数组。其中一些值可能包括各种字符串格式的日期。
I need to convert dates in multiple formats to their numerical equivalent (Unix timestamp). The problem is being able to determine if the string is a date.
我需要将多种格式的日期转换为其等效的数字（Unix 时间戳）。问题是能够确定字符串是否是日期。
Using
使用
if (($timestamp = strtotime($str)) === false)
will check for a valid date from a string but how do I determine if the value should even be validated as a date?
将检查字符串中的有效日期，但如何确定该值是否应该被验证为日期？
Example:
例子：
$x = {1,2,3,"4","11/12/2009","22/12/2000",true,false};
foreach($x as $value)
{
if(is_bool($value))
if(is_string($value))
if(is_numeric($value))
if(is_date($value)) ?
...
}
In short, is there an easy way to check if a string value is a date?
简而言之，是否有一种简单的方法可以检查字符串值是否为日期？
回答by Pekka
In short, is there an easy way to check if a string value is a date?
简而言之，是否有一种简单的方法可以检查字符串值是否为日期？
Not really, seeing as it could be in an arbitrary format.
不是真的，因为它可能是任意格式。
If at all possible, I would tend to leave parsing to the magic of strtotime(). If it manages to create a valid date, fine. If it doesn't, you'll receive false.
如果可能的话，我倾向于将解析留给strtotime(). 如果它设法创建一个有效的日期，那很好。如果没有，您将收到false.
Be prepared for the possibility of false positives, though, because strtotime()parses even things like "Last Friday".
但是，请为误报的可能性做好准备，因为strtotime()甚至会解析诸如“上周五”之类的内容。
If strtotime()is too liberal for you, you could consider building a collection of date formats you want to accept, and run PHP 5.3's DateTime:createFromFormatusing every one of the formats on every date.
如果strtotime()对你来说太自由了，你可以考虑构建一个你想要接受的日期格式的集合，并DateTime:createFromFormat在每个日期使用每一种格式运行 PHP 5.3 。
Something like (untested)
类似的东西（未经测试）
$formats = array("d.m.Y", "d/m/Y", "Ymd"); // and so on.....
$dates = array(1,2,3,"4","11/12/2009","22/12/2000",true,false);
foreach ($dates as $input)
{
foreach ($formats as $format)
{
echo "Applying format $format on date $input...<br>";
$date = DateTime::createFromFormat($format, $input);
if ($date == false)
echo "Failed<br>";
else
echo "Success<br>";
}
}
回答by Dave
The problem with Pekka's script is that the date '2011-30-30' is also considered valid. This is the modified version.
Pekka 脚本的问题在于日期“2011-30-30”也被认为是有效的。这是修改后的版本。
$formats = array("d.m.Y", "d/m/Y", "Ymd"); // and so on.....
$dates = array(1,2,3,"4","11/12/2009","22/12/2000",true,false);
foreach ($dates as $input)
{
foreach ($formats as $format)
{
echo "Applying format $format on date $input...<br>";
$date = DateTime::createFromFormat($format, $input);
if ($date == false || !(date_format($date,$format) == $input) )
echo "Failed<br>";
else
echo "Success<br>";
}
}
回答by iateadonut
Extrapolating from http://au1.php.net/checkdate#113205; just change the $formats array to all the formats you want to check.
从http://au1.php.net/checkdate#113205推断；只需将 $formats 数组更改为您要检查的所有格式。
public function convertDate($value) {
$formats = ['M d, Y', 'Y-m-d'];
foreach($formats as $f) {
$d = DateTime::createFromFormat($f, $value);
$is_date = $d && $d->format($f) === $value;
if ( true == $is_date ) break;
}
return $is_date;
}
