xcode 将 Unichar 转换为 Int 问题
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原文地址: http://stackoverflow.com/questions/4179082/
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Converting Unichar to Int Problem
提问by fabian789
I've got a strange problem trying to convert from unichar to int:
我在尝试从 unichar 转换为 int 时遇到了一个奇怪的问题：
I have a String containing a few numbers, like @"12345". This numbers I want to save individually, meaning I want 5 numbers, 1, 2, 3, ... . Now, while
我有一个包含几个数字的字符串，例如@"12345". 我想单独保存这些数字，这意味着我想要 5 个数字，1、2、3、...。现在，同时
NSLog(@"Value: %C", [myString characterAtIndex:0]);
returns
回报
Value: 1
This:
这个：
NSLog(@"Value: %@", [NSNumber numberWithUnsignedChar:[myString characterAtIndex:0]]);
returns
回报
Value: 49
I would really appreciate some help, Fabian
我真的很感激一些帮助，法比安
回答by Chris Parker
In the code above, you're getting exactly what you're asking for; the numeric value of the character '1'is 49, and you're creating an NSNumber from that.
在上面的代码中，您得到的正是您所要求的；字符的数值'1'是 49，您正在从中创建一个 NSNumber。
If what you want is 1, then you can can take advantage of the fact that the digits 0-9 are laid out in order in the ASCII/UTF-8 tables and subtract an appropriate value from the unichar you receive.
如果您想要的是1，那么您可以利用数字 0-9 在 ASCII/UTF-8 表中按顺序排列的事实，并从您收到的 unichar 中减去一个适当的值。
Try out this code snippet to get you started in the right direction:
试试这个代码片段，让你朝着正确的方向开始：
NSString *s = @"0123456789";
for (int i = 0; i < [s length]; i++) {
NSLog(@"Value: %d", [s characterAtIndex:i]);
}
