php php日期小于另一个日期
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php date less than another date
提问by CQM
given this kind of date object
date("m/d/Y", strtotime($numerical." ".$day." of ".date("F")))
给定这种日期对象
date("m/d/Y", strtotime($numerical." ".$day." of ".date("F")))
where it may give a mm/dd/yyyy day that is the "first Monday of August", for instance
例如，它可能会给出一个 mm/dd/yyyy 天，即“八月的第一个星期一”
how can I decide if this date is greater than, less than, or equal to today's date?
我如何确定这个日期是大于、小于还是等于今天的日期？
I need a now()method that works in this format and can be compared between date objects
我需要一种now()以这种格式工作并且可以在日期对象之间进行比较的方法
I haven't tried date() < date() , yet. But I don't think that will work
我还没有尝试过 date() < date() 。但我认为这行不通
any insight appreciated
任何见解表示赞赏
回答by bwoebi
Compare the timestamps:
比较时间戳：
if (strtotime($numerical." ".$day." of ".date("F")) < time()) {
// older
} else {
// newer
}
This is possible as strtotime()returns the seconds since 1.1.1970 and time()too. And in PHP you can easily compare integers...
这是可能的，因为strtotime()返回自 1.1.1970 以来的秒数time()。在 PHP 中，您可以轻松比较整数...
