Python Seaborn.countplot：按计数排序类别？
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Seaborn.countplot : order categories by count?
提问by nfernand
I know that seaborn.countplothas the attribute orderwhich can be set to determine the order of the categories. But what I would like to do is have the categories be in order of descending count. I know that I can accomplish this by computing the count manually (using a groupbyoperation on the original dataframe, etc.) but I am wondering if this functionality exists with seaborn.countplot. Surprisingly, I cannot find an answer to this question anywhere.
我知道它seaborn.countplot具有order可以设置来确定类别顺序的属性。但我想做的是让类别按降序排列。我知道我可以通过手动计算计数来实现这一点（使用groupby对原始数据帧的操作等），但我想知道这个功能是否存在于seaborn.countplot. 令人惊讶的是，我在任何地方都找不到这个问题的答案。
回答by miradulo
This functionality is not built into seaborn.countplotas far as I know - the orderparameter only accepts a list of strings for the categories, and leaves the ordering logic to the user.
seaborn.countplot据我所知，此功能并未内置- 该order参数仅接受类别的字符串列表，并将排序逻辑留给用户。
This is not hard to do with value_counts()provided you have a DataFrame though. For example,
value_counts()如果你有一个 DataFrame，这并不难。例如，
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
sns.set(style='darkgrid')
titanic = sns.load_dataset('titanic')
sns.countplot(x = 'class',
data = titanic,
order = titanic['class'].value_counts().index)
plt.show()
回答by ImportanceOfBeingErnest
Most often, a seaborn countplot is not really necessary. Just plot with pandas bar plot:
大多数情况下，seaborn 计数图并不是真正必要的。只需绘制熊猫条形图：
import seaborn as sns; sns.set(style='darkgrid')
import matplotlib.pyplot as plt
df = sns.load_dataset('titanic')
df['class'].value_counts().plot(kind="bar")
plt.show()
