jQuery 打开一个新的弹出窗口并将数据发布到其中
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Open a new popup window and post data to it
提问by Pramod
I'm using jQuery to open a popup and I'd like to send it data using the post method when it opens. Can anyone help me, thanks in advance.
我正在使用 jQuery 打开一个弹出窗口，我想在它打开时使用 post 方法向它发送数据。任何人都可以帮助我，在此先感谢。
I am currently passing the data using the get method so the data is a part in url, but I don't want the data to be visible in the url.
我目前正在使用 get 方法传递数据，因此数据是 url 的一部分，但我不希望数据在 url 中可见。
function openWindow(){
var name = $('#name').val();
var url = 'popup_window.php?name='+name;
window.open(
url,
'popUpWindow',
'height=400, \
width=650, \
left=300, \
top=100, \
resizable=yes, \
scrollbars=yes, \
toolbar=yes, \
menubar=no, \
location=no, \
directories=no, \
status=yes');
}
回答by Barmar
This is based on the answer in How to open popup and populate it with data from parent window?
这是基于如何打开弹出窗口并使用父窗口中的数据填充它中的答案？
var newpage;
function openWindow() {
$.post('popup_window.php', {name: $('#name').val()}, function(result) {
newpage = result;
window.open('Popup.html', 'popUpWindow','height=400, width=650, left=300, top=100, resizable=yes, scrollbars=yes, toolbar=yes, menubar=no, location=no, directories=no, status=yes');
});
}
Popup.html should contain:
Popup.html 应包含：
<script type="text/javascript">
if(window.opener && !window.opener.closed) {
document.write(window.opener.newpage);
}
</script>
