bash 使用 sed 和 mv 重命名文件
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Rename files using sed and mv
提问by tiagob
I want to rename files in the format:
我想重命名以下格式的文件：
img_MM-DD-YY_XX.jpg
img_MM-DD-YY_XXX.jpg
img_MM-DD-YY_XX.jpg
img_MM-DD-YY_XXX.jpg
to:
到：
newyears_YYYY-MM-DD_XXX.jpg
newyears_YYYY-MM-DD_XXX.jpg
Where:
在哪里：
- YYYY = year
- MM = month
- DD = day
- XXX or XX = photo number
- YYYY = 年
- MM = 月
- DD = 天
- XXX 或 XX = 照片编号
I came up with this script but it isn't working:
我想出了这个脚本，但它不起作用：
for filename in ?*.jpg; do
newFilename=$(echo $filename | \
sed 's/img_\(.*\)-\(.*\)-\(.*\)_\([0-9][0-9]\)\./newyears_20--_0./;
s/img_\(.*\)-\(.*\)-\(.*\)_\([0-9][0-9][0-9]\)/newyears_20--_/' -)
mv $filename $newFilename
done
Any help would be greatly appreciated.
任何帮助将不胜感激。
回答by anubhava
You can try this script in bash:
你可以在 bash 中尝试这个脚本：
for filename in *.jpg; do
newFilename=$(sed -E 's#img_([0-9]{1,2})-([0-9]{1,2})-([0-9]{1,2})_(.*)$#newyears_20--_#' <<< "$filename")
mv "$filename" "$newFilename"
done
sed -Eis supported by gnu sedalso.
sed -E也支持gnu sed。
回答by earthdan
Without a for loop.
没有 for 循环。
ls | grep 'jpg$' | sed '
#Save the original filename
h
#Do the replacement
s/img_\(.*\)-\(.*\)-\(.*\)_\([0-9][0-9]\)\./newyears_20--_0.//
s/img_\(.*\)-\(.*\)-\(.*\)_\([0-9][0-9][0-9]\)/newyears_20--_//
#Bring the original filename back
x
G
s/^\(.*\)\n\(.*\)$/mv "" ""' | bash
Ommit piping to bash to see the results before mv
在 mv 之前省略管道到 bash 以查看结果
Thanks to http://www.gnu.org/software/sed/manual/sed.html#Rename-files-to-lower-case
感谢http://www.gnu.org/software/sed/manual/sed.html#Rename-files-to-lower-case
回答by Idelic
for f in *.jpg; do
mv $f $(echo newyears_${f#img_} | sed 's/_\(..\)\.jpg/_0.jpg/')
done
回答by Larry Watanabe
I remember messing around with this sort of thing. I found it often useful to create a script that you execute to do what you want:
我记得我在处理这种事情。我发现创建一个脚本来执行你想做的事情通常很有用：
ie. output of your script would be a file like:
IE。脚本的输出将是一个文件，如：
mv file1 file2
mv file3 file4
.....
mv fileN fileM
To create this, just do a ls | grep date pattern| sed script to stick mv file1 to file2> myscript
要创建它，只需执行 ls | grep 日期模式| sed脚本将 mv file1 粘贴到 file2> myscript
then just execute ./myscript
然后只需执行 ./myscript
This way you have a better look at the intermediate output to figure out what's going wrong.
通过这种方式，您可以更好地查看中间输出以找出问题所在。
回答by Jonathan Leffler
This trivial variant works for me:
这个微不足道的变体对我有用：
$ cat mapper
for filename in ?*.jpg
do
newFilename=$(echo $filename | \
sed -e 's/img_\(.*\)-\(.*\)-\(.*\)_\([0-9][0-9]\)\./newyears_20--_0./' \
-e 's/img_\(.*\)-\(.*\)-\(.*\)_\([0-9][0-9][0-9]\)/newyears_20--_/')
echo mv $filename $newFilename
done
$ echo > img_04-23-09_123.jpg
$ echo > img_08-13-08_33.jpg
$ sh mapper
mv img_04-23-09_123.jpg newyears_2009-04-23_123.jpg
mv img_08-13-08_33.jpg newyears_2008-08-13_033.jpg
$
The only difference is the use of the explicit -eoptions in place of a semi-colon.
唯一的区别是使用显式-e选项代替分号。
Tested on MacOS X 10.6.7.
在 MacOS X 10.6.7 上测试。
回答by Yi Zhao
It could be handled by a purely bash script.
它可以由纯粹的 bash 脚本处理。
for j in ?*.jpg
do
n="newyears_20${j:10:2}-${j:4:2}-${j:7:2}";
if [ ${j:15:1} = "." ];then
n="${n}_0${j:13}"
else
n="${n}${j:12}"
fi
mv $j $n
done
回答by kurumi
Ruby(1.9+)
红宝石（1.9+）
$ ruby -e 'Dir["img*jpg"].each{|x|File.rename(x,x.gsub(/img_(.*?)-(.*?)-(.*?)\.jpg/,"newyears_20\2-\1-\3.jpg") )}'
