java 如何忽略 JUnit/easymock 中意外的方法调用？
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How to ignore unexpected method calls in JUnit/easymock?
提问by Rory
I'm just wondering if it is possible using Junit and easymock to ignore unexpected method calls?
我只是想知道是否可以使用 Junit 和 easymock 来忽略意外的方法调用？
I.e. instead of the test failing I want to be able to say - "at this point - ignore any unexpected method calls and just continue with the test as normal'
即，我希望能够说，而不是测试失败 - “此时 - 忽略任何意外的方法调用，然后继续正常进行测试”
Thanks
谢谢
回答by mmccomb
With EasyMock you can create a nice mock, which unlike a normal mock object does not throw assertion errors if an unexpected/recorded call occurs. To quote the easymock documentation...
使用 EasyMock，您可以创建一个很好的模拟，与普通模拟对象不同，如果发生意外/记录的调用，它不会抛出断言错误。引用easymock文档...
On a Mock Object returned by createMock() the default behavior for all methods is to throw an AssertionError for all unexpected method calls. If you would like a "nice" Mock Object that by default allows all method calls and returns appropriate empty values (0, null or false), use createNiceMock() instead.
在 createMock() 返回的 Mock 对象上，所有方法的默认行为是为所有意外方法调用抛出 AssertionError。如果您想要一个默认允许所有方法调用并返回适当的空值（0、null 或 false）的“漂亮”模拟对象，请改用 createNiceMock()。
To create a nice mock, use the static createNiceMock(Class class) method on the Easymock class...
要创建一个不错的模拟，请在 Easymock 类上使用静态 createNiceMock(Class class) 方法...
SomeClass someClassNiceMock = EasyMock.createNiceMock(SomeClass.class);
