Xcode：调试时输入用户输入
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Xcode: entering user input when debugging
提问by nightfire
int main()
{
cout << "Buy or sell (b/s): " << endl;
string buy_sell;
cin >> buy_sell;
.....
}
When i try to step through this in Xcode, it stops at the cin >> buy_sell line, because it's waiting for the user input. How do I enter the value in the debugger? I'm using Xcode 3.2.1.
当我尝试在 Xcode 中逐步执行此操作时，它停在 cin >> buy_sell 行，因为它正在等待用户输入。如何在调试器中输入值？我正在使用 Xcode 3.2.1。
(I know I could just comment out the cin lines and define the variable in the code for debugging purposes, but that would be very tedious, and I feel like there should be an easy way to enter input that I just don't know about.)
（我知道我可以注释掉 cin 行并在代码中定义变量以用于调试目的，但这会非常乏味，而且我觉得应该有一种简单的方法来输入我不知道的输入.)
采纳答案by Oz.
Are you using the XCode console? You can access it under the "Run" menu, just below the Debugger. The shortcut is command-shift-R. From there you can interact with the application exactly like a terminal, but from inside of XCode itself.
你在使用 XCode 控制台吗？您可以在调试器正下方的“运行”菜单下访问它。捷径是command-shift-R。从那里你可以像终端一样与应用程序交互，但从 XCode 本身内部。
回答by Matthew Read
In Xcode 8, the shortcut is ⌘+Shift+C. It seems to be shared with the Output window, by default at the bottom-right.
在 Xcode 8 中，快捷方式是⌘+ Shift+ C。它似乎与输出窗口共享，默认情况下位于右下角。
